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1421. NPV Queries
Description
Table: NPV
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | year | int | | npv | int | +---------------+---------+ (id, year) is the primary key (combination of columns with unique values) of this table. The table has information about the id and the year of each inventory and the corresponding net present value.
Table: Queries
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | year | int | +---------------+---------+ (id, year) is the primary key (combination of columns with unique values) of this table. The table has information about the id and the year of each inventory query.
Write a solution to find the npv
of each query of the Queries
table.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input: NPV table: +------+--------+--------+ | id | year | npv | +------+--------+--------+ | 1 | 2018 | 100 | | 7 | 2020 | 30 | | 13 | 2019 | 40 | | 1 | 2019 | 113 | | 2 | 2008 | 121 | | 3 | 2009 | 12 | | 11 | 2020 | 99 | | 7 | 2019 | 0 | +------+--------+--------+ Queries table: +------+--------+ | id | year | +------+--------+ | 1 | 2019 | | 2 | 2008 | | 3 | 2009 | | 7 | 2018 | | 7 | 2019 | | 7 | 2020 | | 13 | 2019 | +------+--------+ Output: +------+--------+--------+ | id | year | npv | +------+--------+--------+ | 1 | 2019 | 113 | | 2 | 2008 | 121 | | 3 | 2009 | 12 | | 7 | 2018 | 0 | | 7 | 2019 | 0 | | 7 | 2020 | 30 | | 13 | 2019 | 40 | +------+--------+--------+ Explanation: The npv value of (7, 2018) is not present in the NPV table, we consider it 0. The npv values of all other queries can be found in the NPV table.
Solutions
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# Write your MySQL query statement below SELECT q.*, IFNULL(npv, 0) AS npv FROM Queries AS q LEFT JOIN NPV AS n USING (id, year);