# 1333. Filter Restaurants by Vegan-Friendly, Price and Distance

## Description

Given the array restaurants where  restaurants[i] = [idi, ratingi, veganFriendlyi, pricei, distancei]. You have to filter the restaurants using three filters.

The veganFriendly filter will be either true (meaning you should only include restaurants with veganFriendlyi set to true) or false (meaning you can include any restaurant). In addition, you have the filters maxPrice and maxDistance which are the maximum value for price and distance of restaurants you should consider respectively.

Return the array of restaurant IDs after filtering, ordered by rating from highest to lowest. For restaurants with the same rating, order them by id from highest to lowest. For simplicity veganFriendlyi and veganFriendly take value 1 when it is true, and 0 when it is false.

Example 1:

Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 1, maxPrice = 50, maxDistance = 10
Output: [3,1,5]
Explanation:
The restaurants are:
Restaurant 1 [id=1, rating=4, veganFriendly=1, price=40, distance=10]
Restaurant 2 [id=2, rating=8, veganFriendly=0, price=50, distance=5]
Restaurant 3 [id=3, rating=8, veganFriendly=1, price=30, distance=4]
Restaurant 4 [id=4, rating=10, veganFriendly=0, price=10, distance=3]
Restaurant 5 [id=5, rating=1, veganFriendly=1, price=15, distance=1]
After filter restaurants with veganFriendly = 1, maxPrice = 50 and maxDistance = 10 we have restaurant 3, restaurant 1 and restaurant 5 (ordered by rating from highest to lowest).


Example 2:

Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 0, maxPrice = 50, maxDistance = 10
Output: [4,3,2,1,5]
Explanation: The restaurants are the same as in example 1, but in this case the filter veganFriendly = 0, therefore all restaurants are considered.


Example 3:

Input: restaurants = [[1,4,1,40,10],[2,8,0,50,5],[3,8,1,30,4],[4,10,0,10,3],[5,1,1,15,1]], veganFriendly = 0, maxPrice = 30, maxDistance = 3
Output: [4,5]


Constraints:

• 1 <= restaurants.length <= 10^4
• restaurants[i].length == 5
• 1 <= idi, ratingi, pricei, distancei <= 10^5
• 1 <= maxPrice, maxDistance <= 10^5
• veganFriendlyi and veganFriendly are 0 or 1.
• All idi are distinct.

## Solutions

• class Solution {
public List<Integer> filterRestaurants(
int[][] restaurants, int veganFriendly, int maxPrice, int maxDistance) {
Arrays.sort(restaurants, (a, b) -> a[1] == b[1] ? b[0] - a[0] : b[1] - a[1]);
List<Integer> ans = new ArrayList<>();
for (int[] r : restaurants) {
if (r[2] >= veganFriendly && r[3] <= maxPrice && r[4] <= maxDistance) {
}
}
return ans;
}
}

• class Solution {
public:
vector<int> filterRestaurants(vector<vector<int>>& restaurants, int veganFriendly, int maxPrice, int maxDistance) {
sort(restaurants.begin(), restaurants.end(), [](const vector<int>& a, const vector<int>& b) {
if (a[1] != b[1]) {
return a[1] > b[1];
}
return a[0] > b[0];
});
vector<int> ans;
for (auto& r : restaurants) {
if (r[2] >= veganFriendly && r[3] <= maxPrice && r[4] <= maxDistance) {
ans.push_back(r[0]);
}
}
return ans;
}
};

• class Solution:
def filterRestaurants(
self,
restaurants: List[List[int]],
veganFriendly: int,
maxPrice: int,
maxDistance: int,
) -> List[int]:
restaurants.sort(key=lambda x: (-x[1], -x[0]))
ans = []
for idx, _, vegan, price, dist in restaurants:
if vegan >= veganFriendly and price <= maxPrice and dist <= maxDistance:
ans.append(idx)
return ans


• func filterRestaurants(restaurants [][]int, veganFriendly int, maxPrice int, maxDistance int) (ans []int) {
sort.Slice(restaurants, func(i, j int) bool {
a, b := restaurants[i], restaurants[j]
if a[1] != b[1] {
return a[1] > b[1]
}
return a[0] > b[0]
})
for _, r := range restaurants {
if r[2] >= veganFriendly && r[3] <= maxPrice && r[4] <= maxDistance {
ans = append(ans, r[0])
}
}
return
}

• function filterRestaurants(
restaurants: number[][],
veganFriendly: number,
maxPrice: number,
maxDistance: number,
): number[] {
restaurants.sort((a, b) => (a[1] === b[1] ? b[0] - a[0] : b[1] - a[1]));
const ans: number[] = [];
for (const [id, _, vegan, price, distance] of restaurants) {
if (vegan >= veganFriendly && price <= maxPrice && distance <= maxDistance) {
ans.push(id);
}
}
return ans;
}