Formatted question description: https://leetcode.ca/all/1332.html

# 1332. Remove Palindromic Subsequences (Easy)

Given a string s consisting only of letters 'a' and 'b'. In a single step you can remove one palindromic subsequence from s.

Return the minimum number of steps to make the given string empty.

A string is a subsequence of a given string, if it is generated by deleting some characters of a given string without changing its order.

A string is called palindrome if is one that reads the same backward as well as forward.

Example 1:

Input: s = "ababa"
Output: 1


Example 2:

Input: s = "abb"
Output: 2
Explanation: "abb" -> "bb" -> "".
Remove palindromic subsequence "a" then "bb".


Example 3:

Input: s = "baabb"
Output: 2
Explanation: "baabb" -> "b" -> "".
Remove palindromic subsequence "baab" then "b".


Example 4:

Input: s = ""
Output: 0


Constraints:

• 0 <= s.length <= 1000
• s only consists of letters 'a' and 'b'

Related Topics:
String

## Solution 1.

// OJ: https://leetcode.com/problems/remove-palindromic-subsequences/

// Time: O(N)
// Space: O(1)
class Solution {
public:
int removePalindromeSub(string s) {
if (s.empty()) return 0;
bool isPalindrome = true;
for (int i = 0, j = s.size() - 1; i < j && isPalindrome; ++i, --j) {
isPalindrome = s[i] == s[j];
}
return isPalindrome ? 1 : 2;
}
};


Java

class Solution {
public int removePalindromeSub(String s) {
if (s == null || s.length() == 0)
return 0;
int low = 0, high = s.length() - 1;
while (low < high) {
if (s.charAt(low) == s.charAt(high)) {
low++;
high--;
} else
return 2;
}
return 1;
}
}