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• /**

A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner.

Two rectangles overlap if the area of their intersection is positive.  To be clear, two rectangles that only touch at the corner or edges do not overlap.

Given two (axis-aligned) rectangles, return whether they overlap.

Example 1:

Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3]
Output: true
Example 2:

Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1]
Output: false
Notes:

Both rectangles rec1 and rec2 are lists of 4 integers.
All coordinates in rectangles will be between -10^9 and 10^9.

*/

import javafx.util.Pair;

public class Rectangle_Overlap {

public static void main(String[] args) {

Rectangle_Overlap out = new Rectangle_Overlap();
Solution s = out.new Solution();

int[] a = new int[]{0,0,2,2};
int[] b = new int[]{1,1,3,3};

System.out.println(s.isRectangleOverlap(a, b));

}

class Solution {
public boolean isRectangleOverlap(int[] rec1, int[] rec2) {
if (rec1 == null || rec1.length == 0 || rec2 == null || rec2.length == 0
|| rec1.length != 4 || rec2.length != 4) {
return false;
}

// rectangles abstracted to 2 lines
// overlap meaning, both lines are overlapping
Pair<Integer, Integer> rec1horizontal = new Pair<>(rec1, rec1);
Pair<Integer, Integer> rec1vertical = new Pair<>(rec1, rec1);

Pair<Integer, Integer> rec2horizontal = new Pair<>(rec2, rec2);
Pair<Integer, Integer> rec2vertical = new Pair<>(rec2, rec2);

return isOverlap(rec1horizontal, rec2horizontal) && isOverlap(rec1vertical, rec2vertical);
}

private boolean isOverlap(Pair<Integer, Integer> line1, Pair<Integer, Integer> line2) {

return !(line1.getValue() <= line2.getKey() || line1.getKey() >= line2.getValue());
}
}

}

• // OJ: https://leetcode.com/problems/rectangle-overlap
// Time: O(1)
// Space: O(1)
class Solution {
public:
bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) {
return (rec2 < rec1 && rec2 > rec1
&& rec1 < rec2 && rec1 > rec2);
}
};

• class Solution:
def isRectangleOverlap(self, rec1, rec2):
"""
:type rec1: List[int]
:type rec2: List[int]
:rtype: bool
"""
rec1_x1, rec1_y1, rec1_x2, rec1_y2 = rec1
rec2_x1, rec2_y1, rec2_x2, rec2_y2 = rec2
return not (rec1_x1 >= rec2_x2 or rec1_x2 <= rec2_x1 or rec1_y1 >= rec2_y2 or rec1_y2 <= rec2_y1)

• func isRectangleOverlap(rec1 []int, rec2 []int) bool {
x1, y1, x2, y2 := rec1, rec1, rec1, rec1
x3, y3, x4, y4 := rec2, rec2, rec2, rec2
return !(y3 >= y2 || y4 <= y1 || x3 >= x2 || x4 <= x1)
}

• class Solution {
public boolean isRectangleOverlap(int[] rec1, int[] rec2) {
return rec1 > rec2 && rec1 < rec2 && rec1 > rec2 && rec1 < rec2;
}
}

• // OJ: https://leetcode.com/problems/rectangle-overlap
// Time: O(1)
// Space: O(1)
class Solution {
public:
bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) {
return (rec2 < rec1 && rec2 > rec1
&& rec1 < rec2 && rec1 > rec2);
}
};

• class Solution:
def isRectangleOverlap(self, rec1, rec2):
"""
:type rec1: List[int]
:type rec2: List[int]
:rtype: bool
"""
rec1_x1, rec1_y1, rec1_x2, rec1_y2 = rec1
rec2_x1, rec2_y1, rec2_x2, rec2_y2 = rec2
return not (rec1_x1 >= rec2_x2 or rec1_x2 <= rec2_x1 or rec1_y1 >= rec2_y2 or rec1_y2 <= rec2_y1)

• func isRectangleOverlap(rec1 []int, rec2 []int) bool {
x1, y1, x2, y2 := rec1, rec1, rec1, rec1
x3, y3, x4, y4 := rec2, rec2, rec2, rec2
return !(y3 >= y2 || y4 <= y1 || x3 >= x2 || x4 <= x1)
}