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Formatted question description: https://leetcode.ca/all/825.html

# 825. Friends Of Appropriate Ages (Medium)

Some people will make friend requests. The list of their ages is given and ages[i] is the age of the ith person.

Person A will NOT friend request person B (B != A) if any of the following conditions are true:

• age[B] <= 0.5 * age[A] + 7
• age[B] > age[A]
• age[B] > 100 && age[A] < 100

Otherwise, A will friend request B.

Note that if A requests B, B does not necessarily request A.  Also, people will not friend request themselves.

How many total friend requests are made?

Example 1:

Input: [16,16]
Output: 2
Explanation: 2 people friend request each other.


Example 2:

Input: [16,17,18]
Output: 2
Explanation: Friend requests are made 17 -> 16, 18 -> 17.

Example 3:

Input: [20,30,100,110,120]
Output:
Explanation: Friend requests are made 110 -> 100, 120 -> 110, 120 -> 100.


Notes:

• 1 <= ages.length <= 20000.
• 1 <= ages[i] <= 120.

Companies:

Related Topics:
Array

## Solution 1.

• class Solution {
public int numFriendRequests(int[] ages) {
Arrays.sort(ages);
Map<Integer, Integer> ageCountMap = new HashMap<Integer, Integer>();
for (int age : ages) {
int count = ageCountMap.getOrDefault(age, 0) + 1;
ageCountMap.put(age, count);
}
int friendRequests = 0;
int length = ages.length;
for (int i = 0; i < length; i++) {
if (i > 0 && ages[i] == ages[i - 1])
continue;
int age = ages[i];
int minAge = age / 2 + 8;
if (minAge > age)
continue;
int minIndex = binarySearch(ages, minAge);
int count = ageCountMap.get(age);
friendRequests += count * (i - minIndex);
friendRequests += count * (count - 1);
}
return friendRequests;
}

public int binarySearch(int[] ages, int minAge) {
int low = 0, high = ages.length - 1;
while (low < high) {
int mid = (high - low) / 2 + low;
int age = ages[mid];
if (age < minAge)
low = mid + 1;
else
high = mid;
}
return low;
}
}

############

class Solution {
public int numFriendRequests(int[] ages) {
int[] counter = new int[121];
for (int age : ages) {
++counter[age];
}
int ans = 0;
for (int i = 1; i < 121; ++i) {
int n1 = counter[i];
for (int j = 1; j < 121; ++j) {
int n2 = counter[j];
if (!(j <= 0.5 * i + 7 || j > i || (j > 100 && i < 100))) {
ans += n1 * n2;
if (i == j) {
ans -= n2;
}
}
}
}
return ans;
}
}

• // OJ: https://leetcode.com/problems/friends-of-appropriate-ages/
// Time: O(N)
// Space: O(1)
class Solution {
private:
bool request(int A, int B) {
return !(B <= .5 * A + 7 || B > A);
}
public:
int numFriendRequests(vector<int>& ages) {
int ans = 0;
vector<int> cnts(120, 0);
for (int age : ages) cnts[age - 1]++;
for (int i = 0; i < 120; ++i) {
if (!cnts[i]) continue;
for (int j = 0; j < 120; ++j) {
if (!cnts[j] || !request(i + 1, j + 1)) continue;
ans += cnts[i] * cnts[j];
if (i == j) ans -= cnts[i];
}
}
return ans;
}
};

• class Solution:
def numFriendRequests(self, ages: List[int]) -> int:
counter = Counter(ages)
ans = 0
for i in range(1, 121):
n1 = counter[i]
for j in range(1, 121):
n2 = counter[j]
if not (j <= 0.5 * i + 7 or j > i or (j > 100 and i < 100)):
ans += n1 * n2
if i == j:
ans -= n2
return ans

############

class Solution(object):
def numFriendRequests(self, ages):
"""
:type ages: List[int]
:rtype: int
"""
count = collections.Counter(ages)
ages = sorted(count.keys())
N = len(ages)
res = 0
for A in ages:
for B in range(int(0.5 * A) + 7 + 1, A + 1):
res += count[A] * (count[B] - int(A == B))
return res

• func numFriendRequests(ages []int) int {
counter := make([]int, 121)
for _, age := range ages {
counter[age]++
}
ans := 0
for i := 1; i < 121; i++ {
n1 := counter[i]
for j := 1; j < 121; j++ {
n2 := counter[j]
if !(j <= i/2+7 || j > i || (j > 100 && i < 100)) {
ans += n1 * n2
if i == j {
ans -= n2
}
}
}
}
return ans
}