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Formatted question description: https://leetcode.ca/all/2303.html

2303. Calculate Amount Paid in Taxes

  • Difficulty: Easy.
  • Related Topics: Array, Simulation.
  • Similar Questions: .

Problem

You are given a 0-indexed 2D integer array brackets where brackets[i] = [upperi, percenti] means that the ith tax bracket has an upper bound of upperi and is taxed at a rate of percenti. The brackets are sorted by upper bound (i.e. upperi-1 < upperi for 0 < i < brackets.length).

Tax is calculated as follows:

  • The first upper0 dollars earned are taxed at a rate of percent0.

  • The next upper1 - upper0 dollars earned are taxed at a rate of percent1.

  • The next upper2 - upper1 dollars earned are taxed at a rate of percent2.

  • And so on.

You are given an integer income representing the amount of money you earned. Return the amount of money that you have to pay in taxes. Answers within 10-5 of the actual answer will be accepted.

  Example 1:

Input: brackets = [[3,50],[7,10],[12,25]], income = 10
Output: 2.65000
Explanation:
Based on your income, you have 3 dollars in the 1st tax bracket, 4 dollars in the 2nd tax bracket, and 3 dollars in the 3rd tax bracket.
The tax rate for the three tax brackets is 50%, 10%, and 25%, respectively.
In total, you pay $3 * 50% + $4 * 10% + $3 * 25% = $2.65 in taxes.

Example 2:

Input: brackets = [[1,0],[4,25],[5,50]], income = 2
Output: 0.25000
Explanation:
Based on your income, you have 1 dollar in the 1st tax bracket and 1 dollar in the 2nd tax bracket.
The tax rate for the two tax brackets is 0% and 25%, respectively.
In total, you pay $1 * 0% + $1 * 25% = $0.25 in taxes.

Example 3:

Input: brackets = [[2,50]], income = 0
Output: 0.00000
Explanation:
You have no income to tax, so you have to pay a total of $0 in taxes.

  Constraints:

  • 1 <= brackets.length <= 100

  • 1 <= upperi <= 1000

  • 0 <= percenti <= 100

  • 0 <= income <= 1000

  • upperi is sorted in ascending order.

  • All the values of upperi are unique.

  • The upper bound of the last tax bracket is greater than or equal to income.

Solution (Java, C++, Python)

  • class Solution {
    public double calculateTax(int[][] brackets, int income) {
        // you can remove this line
        if (income == 0) {
            return 0;
        }
        double sum = 0;
        double prev = 0;
        for (int[] bracket : brackets) {
            double salary = Math.min(bracket[0], income);
            double tax = bracket[1];
            sum += (salary - prev) * tax;
            prev = salary;
        }
        return sum / 100;
    }
}

############

class Solution {
    public double calculateTax(int[][] brackets, int income) {
        int ans = 0, prev = 0;
        for (var e : brackets) {
            int upper = e[0], percent = e[1];
            ans += Math.max(0, Math.min(income, upper) - prev) * percent;
            prev = upper;
        }
        return ans / 100.0;
    }
}

  • class Solution:
    def calculateTax(self, brackets: List[List[int]], income: int) -> float:
        ans = prev = 0
        for upper, percent in brackets:
            ans += max(0, min(income, upper) - prev) * percent
            prev = upper
        return ans / 100

############

# 2303. Calculate Amount Paid in Taxes
# https://leetcode.com/problems/calculate-amount-paid-in-taxes/

class Solution:
    def calculateTax(self, brackets: List[List[int]], income: int) -> float:
        n = len(brackets)
        first = min(brackets[0][0], income)
        res =  first * (brackets[0][1] / 100)
        income -= first
        
        for i in range(1, n):
            k = brackets[i][0] - brackets[i - 1][0]
            curr = min(income, k)
            income -= curr
            res += curr * (brackets[i][1] / 100)
            
            if income == 0:
                break
        
        return res


  • class Solution {
public:
    double calculateTax(vector<vector<int>>& brackets, int income) {
        int ans = 0, prev = 0;
        for (auto& e : brackets) {
            int upper = e[0], percent = e[1];
            ans += max(0, min(income, upper) - prev) * percent;
            prev = upper;
        }
        return ans / 100.0;
    }
};

  • func calculateTax(brackets [][]int, income int) float64 {
	var ans, prev int
	for _, e := range brackets {
		upper, percent := e[0], e[1]
		ans += max(0, min(income, upper)-prev) * percent
		prev = upper
	}
	return float64(ans) / 100.0
}

func max(a, b int) int {
	if a > b {
		return a
	}
	return b
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}

  • function calculateTax(brackets: number[][], income: number): number {
    let ans = 0;
    let prev = 0;
    for (const [upper, percent] of brackets) {
        ans += Math.max(0, Math.min(income, upper) - prev) * percent;
        prev = upper;
    }
    return ans / 100;
}


  • impl Solution {
    pub fn calculate_tax(brackets: Vec<Vec<i32>>, income: i32) -> f64 {
        let mut res = 0f64;
        let mut pre = 0i32;
        for bracket in brackets.iter() {
            res += f64::from(income.min(bracket[0]) - pre) * f64::from(bracket[1]) * 0.01;
            if income <= bracket[0] {
                break;
            }
            pre = bracket[0];
        }
        res
    }
}

Explain:

nope.

Complexity:

  • Time complexity : O(n).
  • Space complexity : O(n).

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