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2352. Equal Row and Column Pairs
Description
Given a 0-indexed n x n
integer matrix grid
, return the number of pairs (ri, cj)
such that row ri
and column cj
are equal.
A row and column pair is considered equal if they contain the same elements in the same order (i.e., an equal array).
Example 1:
Input: grid = [[3,2,1],[1,7,6],[2,7,7]] Output: 1 Explanation: There is 1 equal row and column pair: - (Row 2, Column 1): [2,7,7]
Example 2:
Input: grid = [[3,1,2,2],[1,4,4,5],[2,4,2,2],[2,4,2,2]] Output: 3 Explanation: There are 3 equal row and column pairs: - (Row 0, Column 0): [3,1,2,2] - (Row 2, Column 2): [2,4,2,2] - (Row 3, Column 2): [2,4,2,2]
Constraints:
n == grid.length == grid[i].length
1 <= n <= 200
1 <= grid[i][j] <= 105
Solutions
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class Solution { public int equalPairs(int[][] grid) { int n = grid.length; int[][] g = new int[n][n]; for (int j = 0; j < n; ++j) { for (int i = 0; i < n; ++i) { g[i][j] = grid[j][i]; } } int ans = 0; for (var row : grid) { for (var col : g) { int ok = 1; for (int i = 0; i < n; ++i) { if (row[i] != col[i]) { ok = 0; break; } } ans += ok; } } return ans; } }
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class Solution { public: int equalPairs(vector<vector<int>>& grid) { int n = grid.size(); vector<vector<int>> g(n, vector<int>(n)); for (int j = 0; j < n; ++j) { for (int i = 0; i < n; ++i) { g[i][j] = grid[j][i]; } } int ans = 0; for (auto& row : grid) { for (auto& col : g) { ans += row == col; } } return ans; } };
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class Solution: def equalPairs(self, grid: List[List[int]]) -> int: g = [list(col) for col in zip(*grid)] return sum(row == col for row in grid for col in g)
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func equalPairs(grid [][]int) (ans int) { n := len(grid) g := make([][]int, n) for i := range g { g[i] = make([]int, n) for j := 0; j < n; j++ { g[i][j] = grid[j][i] } } for _, row := range grid { for _, col := range g { ok := 1 for i, v := range row { if v != col[i] { ok = 0 break } } ans += ok } } return }
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function equalPairs(grid: number[][]): number { const n = grid.length; const g = Array.from({ length: n }, () => Array.from({ length: n }, () => 0)); for (let j = 0; j < n; ++j) { for (let i = 0; i < n; ++i) { g[i][j] = grid[j][i]; } } let ans = 0; for (const row of grid) { for (const col of g) { ans += Number(row.toString() === col.toString()); } } return ans; }