Welcome to Subscribe On Youtube

2177. Find Three Consecutive Integers That Sum to a Given Number

Description

Given an integer num, return three consecutive integers (as a sorted array) that sum to num. If num cannot be expressed as the sum of three consecutive integers, return an empty array.

 

Example 1:

Input: num = 33
Output: [10,11,12]
Explanation: 33 can be expressed as 10 + 11 + 12 = 33.
10, 11, 12 are 3 consecutive integers, so we return [10, 11, 12].

Example 2:

Input: num = 4
Output: []
Explanation: There is no way to express 4 as the sum of 3 consecutive integers.

 

Constraints:

• 0 <= num <= 1015

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public long[] sumOfThree(long num) {
          if (num % 3 != 0) {
              return new long[] {};
          }
          long x = num / 3;
          return new long[] {x - 1, x, x + 1};
      }
  }
  

• class Solution {
  public:
      vector<long long> sumOfThree(long long num) {
          if (num % 3) {
              return {};
          }
          long long x = num / 3;
          return {x - 1, x, x + 1};
      }
  };
  

• class Solution:
      def sumOfThree(self, num: int) -> List[int]:
          x, mod = divmod(num, 3)
          return [] if mod else [x - 1, x, x + 1]
  
  

• func sumOfThree(num int64) []int64 {
  	if num%3 != 0 {
  		return []int64{}
  	}
  	x := num / 3
  	return []int64{x - 1, x, x + 1}
  }
  

• function sumOfThree(num: number): number[] {
      if (num % 3) {
          return [];
      }
      const x = Math.floor(num / 3);
      return [x - 1, x, x + 1];
  }
  
  

All Problems

All Solutions