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2089. Find Target Indices After Sorting Array

Description

You are given a 0-indexed integer array nums and a target element target.

A target index is an index i such that nums[i] == target.

Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

 

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.

Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.

Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.

 

Constraints:

• 1 <= nums.length <= 100
• 1 <= nums[i], target <= 100

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public List<Integer> targetIndices(int[] nums, int target) {
          Arrays.sort(nums);
          List<Integer> ans = new ArrayList<>();
          for (int i = 0; i < nums.length; ++i) {
              if (nums[i] == target) {
                  ans.add(i);
              }
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      vector<int> targetIndices(vector<int>& nums, int target) {
          sort(nums.begin(), nums.end());
          vector<int> ans;
          for (int i = 0; i < nums.size(); ++i) {
              if (nums[i] == target) {
                  ans.push_back(i);
              }
          }
          return ans;
      }
  };
  

• class Solution:
      def targetIndices(self, nums: List[int], target: int) -> List[int]:
          nums.sort()
          return [i for i, v in enumerate(nums) if v == target]
  
  

• func targetIndices(nums []int, target int) (ans []int) {
  	sort.Ints(nums)
  	for i, v := range nums {
  		if v == target {
  			ans = append(ans, i)
  		}
  	}
  	return
  }
  

• function targetIndices(nums: number[], target: number): number[] {
      nums.sort((a, b) => a - b);
      let ans: number[] = [];
      for (let i = 0; i < nums.length; ++i) {
          if (nums[i] == target) {
              ans.push(i);
          }
      }
      return ans;
  }
  
  

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