# 2089. Find Target Indices After Sorting Array

## Description

You are given a 0-indexed integer array nums and a target element target.

A target index is an index i such that nums[i] == target.

Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.


Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.


Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.


Constraints:

• 1 <= nums.length <= 100
• 1 <= nums[i], target <= 100

## Solutions

• class Solution {
public List<Integer> targetIndices(int[] nums, int target) {
Arrays.sort(nums);
List<Integer> ans = new ArrayList<>();
for (int i = 0; i < nums.length; ++i) {
if (nums[i] == target) {
}
}
return ans;
}
}

• class Solution {
public:
vector<int> targetIndices(vector<int>& nums, int target) {
sort(nums.begin(), nums.end());
vector<int> ans;
for (int i = 0; i < nums.size(); ++i) {
if (nums[i] == target) {
ans.push_back(i);
}
}
return ans;
}
};

• class Solution:
def targetIndices(self, nums: List[int], target: int) -> List[int]:
nums.sort()
return [i for i, v in enumerate(nums) if v == target]


• func targetIndices(nums []int, target int) (ans []int) {
sort.Ints(nums)
for i, v := range nums {
if v == target {
ans = append(ans, i)
}
}
return
}

• function targetIndices(nums: number[], target: number): number[] {
nums.sort((a, b) => a - b);
let ans: number[] = [];
for (let i = 0; i < nums.length; ++i) {
if (nums[i] == target) {
ans.push(i);
}
}
return ans;
}