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Formatted question description: https://leetcode.ca/all/1795.html
Level
Easy
Description
Table: Products
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| product_id | int |
| store1 | int |
| store2 | int |
| store3 | int |
+-------------+---------+
product_id is the primary key for this table.
Each row in this table indicates the product's price in 3 different stores: store1, store2, and store3.
If the product is not available in a store, the price will be null in that store's column.
Write an SQL query to rearrange the Products
table so that each row has (product_id, store, price)
. If a product is not available in a store, do not include a row with that product_id
and store
combination in the result table.
Return the result table in any order.
The query result format is in the following example:
Products table:
+------------+--------+--------+--------+
| product_id | store1 | store2 | store3 |
+------------+--------+--------+--------+
| 0 | 95 | 100 | 105 |
| 1 | 70 | null | 80 |
+------------+--------+--------+--------+
Result table:
+------------+--------+-------+
| product_id | store | price |
+------------+--------+-------+
| 0 | store1 | 95 |
| 0 | store2 | 100 |
| 0 | store3 | 105 |
| 1 | store1 | 70 |
| 1 | store3 | 80 |
+------------+--------+-------+
Product 0 is available in all three stores with prices 95, 100, and 105 respectively.
Product 1 is available in store1 with price 70 and store3 with price 80. The product is not available in store2.
Solution
Select the entries for each product_id
and the corresponding store
and price
. Use union all
to union the entries of the three stores.
# Write your MySQL query statement below
select product_id, 'store1' as store, store1 as price from Products where store1 is not null
union all
select product_id, 'store2' as store, store2 as price from Products where store2 is not null
union all
select product_id, 'store3' as store, store3 as price from Products where store3 is not null;