Formatted question description: https://leetcode.ca/all/1796.html
1796. Second Largest Digit in a String
Level
Easy
Description
Given an alphanumeric string s
, return the second largest numerical digit that appears in s
, or -1
if it does not exist.
An alphanumeric string is a string consisting of lowercase English letters and digits.
Example 1:
Input: s = “dfa12321afd”
Output: 2
Explanation: The digits that appear in s are [1, 2, 3]. The second largest digit is 2.
Example 2:
Input: s = “abc1111”
Output: -1
Explanation: The digits that appear in s are [1]. There is no second largest digit.
Constraints:
1 <= s.length <= 500
s
consists of only lowercase English letters and/or digits.
Solution
Loop over s
and count the occurrences of all digits. Then loop over all digits backwards and find the second largest digit that has occurrence greater than 0. If such a digit exists, return the digit. Otherwise, return -1.
class Solution {
public int secondHighest(String s) {
int[] counts = new int[10];
int length = s.length();
for (int i = 0; i < length; i++) {
char c = s.charAt(i);
if (c >= '0' && c <= '9')
counts[c - '0']++;
}
boolean flag = false;
for (int i = 9; i >= 0; i--) {
if (counts[i] > 0) {
if (!flag)
flag = true;
else
return i;
}
}
return -1;
}
}