# 1941. Check if All Characters Have Equal Number of Occurrences

## Description

Given a string s, return true if s is a good string, or false otherwise.

A string s is good if all the characters that appear in s have the same number of occurrences (i.e., the same frequency).

Example 1:

Input: s = "abacbc"
Output: true
Explanation: The characters that appear in s are 'a', 'b', and 'c'. All characters occur 2 times in s.


Example 2:

Input: s = "aaabb"
Output: false
Explanation: The characters that appear in s are 'a' and 'b'.
'a' occurs 3 times while 'b' occurs 2 times, which is not the same number of times.


Constraints:

• 1 <= s.length <= 1000
• s consists of lowercase English letters.

## Solutions

• class Solution {
public boolean areOccurrencesEqual(String s) {
int[] cnt = new int[26];
for (int i = 0; i < s.length(); ++i) {
++cnt[s.charAt(i) - 'a'];
}
int x = 0;
for (int v : cnt) {
if (v > 0) {
if (x == 0) {
x = v;
} else if (x != v) {
return false;
}
}
}
return true;
}
}

• class Solution {
public:
bool areOccurrencesEqual(string s) {
int cnt[26]{};
for (char& c : s) {
++cnt[c - 'a'];
}
int x = 0;
for (int& v : cnt) {
if (v) {
if (!x) {
x = v;
} else if (x != v) {
return false;
}
}
}
return true;
}
};

• class Solution:
def areOccurrencesEqual(self, s: str) -> bool:
cnt = Counter(s)
return len(set(cnt.values())) == 1


• func areOccurrencesEqual(s string) bool {
cnt := [26]int{}
for _, c := range s {
cnt[c-'a']++
}
x := 0
for _, v := range cnt {
if v > 0 {
if x == 0 {
x = v
} else if x != v {
return false
}
}
}
return true
}

• function areOccurrencesEqual(s: string): boolean {
const cnt: number[] = new Array(26).fill(0);
for (const c of s) {
++cnt[c.charCodeAt(0) - 'a'.charCodeAt(0)];
}
let x = 0;
for (const v of cnt) {
if (v) {
if (!x) {
x = v;
} else if (x !== v) {
return false;
}
}
}
return true;
}


• class Solution {
/**
* @param String $s * @return Boolean */ function areOccurrencesEqual($s) {
for ($i = 0;$i < strlen($s);$i++) {
$hashtable[$s[$i]] += 1; }$rs = array_unique($hashtable); return count($rs) === 1;
}
}