Welcome to Subscribe On Youtube

1662. Check If Two String Arrays are Equivalent

Description

Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise.

A string is represented by an array if the array elements concatenated in order forms the string.

 

Example 1:

Input: word1 = ["ab", "c"], word2 = ["a", "bc"]
Output: true
Explanation:
word1 represents string "ab" + "c" -> "abc"
word2 represents string "a" + "bc" -> "abc"
The strings are the same, so return true.

Example 2:

Input: word1 = ["a", "cb"], word2 = ["ab", "c"]
Output: false

Example 3:

Input: word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
Output: true

 

Constraints:

  • 1 <= word1.length, word2.length <= 103
  • 1 <= word1[i].length, word2[i].length <= 103
  • 1 <= sum(word1[i].length), sum(word2[i].length) <= 103
  • word1[i] and word2[i] consist of lowercase letters.

Solutions

  • class Solution {
    public boolean arrayStringsAreEqual(String[] word1, String[] word2) {
        return String.join("", word1).equals(String.join("", word2));
    }
}

  • class Solution {
public:
    bool arrayStringsAreEqual(vector<string>& word1, vector<string>& word2) {
        return reduce(word1.cbegin(), word1.cend()) == reduce(word2.cbegin(), word2.cend());
    }
};

  • class Solution:
    def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
        return ''.join(word1) == ''.join(word2)


  • func arrayStringsAreEqual(word1 []string, word2 []string) bool {
	return strings.Join(word1, "") == strings.Join(word2, "")
}

  • function arrayStringsAreEqual(word1: string[], word2: string[]): boolean {
    return word1.join('') === word2.join('');
}


  • impl Solution {
    pub fn array_strings_are_equal(word1: Vec<String>, word2: Vec<String>) -> bool {
        word1.join("") == word2.join("")
    }
}

All Problems

All Solutions