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1507. Reformat Date

Description

Given a date string in the form Day Month Year, where:

  • Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
  • Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
  • Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

  • YYYY denotes the 4 digit year.
  • MM denotes the 2 digit month.
  • DD denotes the 2 digit day.

 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

  • The given dates are guaranteed to be valid, so no error handling is necessary.

Solutions

  • class Solution {
        public String reformatDate(String date) {
            var s = date.split(" ");
            String months = " JanFebMarAprMayJunJulAugSepOctNovDec";
            int day = Integer.parseInt(s[0].substring(0, s[0].length() - 2));
            int month = months.indexOf(s[1]) / 3 + 1;
            return String.format("%s-%02d-%02d", s[2], month, day);
        }
    }
    
  • class Solution {
    public:
        string reformatDate(string date) {
            string months = " JanFebMarAprMayJunJulAugSepOctNovDec";
            stringstream ss(date);
            string year, month, t;
            int day;
            ss >> day >> t >> month >> year;
            month = to_string(months.find(month) / 3 + 1);
            return year + "-" + (month.size() == 1 ? "0" + month : month) + "-" + (day > 9 ? "" : "0") + to_string(day);
        }
    };
    
  • class Solution:
        def reformatDate(self, date: str) -> str:
            s = date.split()
            s.reverse()
            months = " JanFebMarAprMayJunJulAugSepOctNovDec"
            s[1] = str(months.index(s[1]) // 3 + 1).zfill(2)
            s[2] = s[2][:-2].zfill(2)
            return "-".join(s)
    
    
  • func reformatDate(date string) string {
    	s := strings.Split(date, " ")
    	day, _ := strconv.Atoi(s[0][:len(s[0])-2])
    	months := " JanFebMarAprMayJunJulAugSepOctNovDec"
    	month := strings.Index(months, s[1])/3 + 1
    	year, _ := strconv.Atoi(s[2])
    	return fmt.Sprintf("%d-%02d-%02d", year, month, day)
    }
    
  • function reformatDate(date: string): string {
        const s = date.split(' ');
        const months = ' JanFebMarAprMayJunJulAugSepOctNovDec';
        const day = parseInt(s[0].substring(0, s[0].length - 2));
        const month = Math.floor(months.indexOf(s[1]) / 3) + 1;
        return `${s[2]}-${month.toString().padStart(2, '0')}-${day.toString().padStart(2, '0')}`;
    }
    
    
  • class Solution {
        /**
         * @param String $date
         * @return String
         */
        function reformatDate($date) {
            $arr = explode(' ', $date);
            $months = [
                'Jan' => '01',
                'Feb' => '02',
                'Mar' => '03',
                'Apr' => '04',
                'May' => '05',
                'Jun' => '06',
                'Jul' => '07',
                'Aug' => '08',
                'Sep' => '09',
                'Oct' => '10',
                'Nov' => '11',
                'Dec' => '12',
            ];
            $year = $arr[2];
            $month = $months[$arr[1]];
            $day = intval($arr[0]);
            if ($day > 0 && $day < 10) {
                $day = '0' . $day;
            }
            return $year . '-' . $month . '-' . $day;
        }
    }
    
    

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