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Formatted question description: https://leetcode.ca/all/1507.html

# 1507. Reformat Date (Easy)

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"


Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"


Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"


Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Related Topics:
String

## Solution 1.

• class Solution {
public String reformatDate(String date) {
String[] months = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};
Map<String, Integer> map = new HashMap<String, Integer>();
for (int i = 1; i <= 12; i++)
map.put(months[i - 1], i);
String[] array = date.split(" ");
int year = Integer.parseInt(array[2]);
int month = map.get(array[1]);
int day = Integer.parseInt(array[0].substring(0, array[0].length() - 2));
return String.format("%d-%02d-%02d", year, month, day);
}
}

############

class Solution {
public String reformatDate(String date) {
var s = date.split(" ");
String months = " JanFebMarAprMayJunJulAugSepOctNovDec";
int day = Integer.parseInt(s[0].substring(0, s[0].length() - 2));
int month = months.indexOf(s[1]) / 3 + 1;
return String.format("%s-%02d-%02d", s[2], month, day);
}
}

• // OJ: https://leetcode.com/problems/reformat-date/
// Time: O(1)
// Space: O(1)
class Solution {
public:
string reformatDate(string date) {
istringstream ss(date);
string day, mon, year, m;
ss >> day >> mon >> year;
if (mon == "Jan") m = "01";
else if (mon == "Feb") m = "02";
else if (mon == "Mar") m = "03";
else if (mon == "Apr") m = "04";
else if (mon == "May") m = "05";
else if (mon == "Jun") m = "06";
else if (mon == "Jul") m = "07";
else if (mon == "Aug") m = "08";
else if (mon == "Sep") m = "09";
else if (mon == "Oct") m = "10";
else if (mon == "Nov") m = "11";
else m = "12";
string d = to_string(stoi(day));
return year + "-" + m + "-" + (d.size() == 1? "0" + d : d);
}
};

• class Solution:
def reformatDate(self, date: str) -> str:
s = date.split()
s.reverse()
months = " JanFebMarAprMayJunJulAugSepOctNovDec"
s[1] = str(months.index(s[1]) // 3 + 1).zfill(2)
s[2] = s[2][:-2].zfill(2)
return "-".join(s)


• func reformatDate(date string) string {
s := strings.Split(date, " ")
day, _ := strconv.Atoi(s[0][:len(s[0])-2])
months := " JanFebMarAprMayJunJulAugSepOctNovDec"
month := strings.Index(months, s[1])/3 + 1
year, _ := strconv.Atoi(s[2])
return fmt.Sprintf("%d-%02d-%02d", year, month, day)
}

• class Solution {
/**
* @param String $date * @return String */ function reformatDate($date) {
$arr = explode(" ",$date);
$months = array("Jan" => "01", "Feb" => "02", "Mar" => "03", "Apr" => "04", "May" => "05", "Jun" => "06", "Jul" => "07", "Aug" => "08", "Sep" => "09", "Oct" => "10", "Nov" => "11", "Dec" => "12");$year = $arr[2];$month = $months[$arr[1]];
$day = intval($arr[0]);
if ($day > 0 &&$day < 10) $day = "0".$day;
return $year."-".$month."-".$day; } }  • function reformatDate(date: string): string { const s = date.split(' '); const months = ' JanFebMarAprMayJunJulAugSepOctNovDec'; const day = parseInt(s[0].substring(0, s[0].length - 2)); const month = Math.floor(months.indexOf(s[1]) / 3) + 1; return ${s[2]}-${month.toString().padStart(2, '0')}-${day
.toString()