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1507. Reformat Date

Description

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• Php

• class Solution {
      public String reformatDate(String date) {
          var s = date.split(" ");
          String months = " JanFebMarAprMayJunJulAugSepOctNovDec";
          int day = Integer.parseInt(s[0].substring(0, s[0].length() - 2));
          int month = months.indexOf(s[1]) / 3 + 1;
          return String.format("%s-%02d-%02d", s[2], month, day);
      }
  }
  

• class Solution {
  public:
      string reformatDate(string date) {
          string months = " JanFebMarAprMayJunJulAugSepOctNovDec";
          stringstream ss(date);
          string year, month, t;
          int day;
          ss >> day >> t >> month >> year;
          month = to_string(months.find(month) / 3 + 1);
          return year + "-" + (month.size() == 1 ? "0" + month : month) + "-" + (day > 9 ? "" : "0") + to_string(day);
      }
  };
  

• class Solution:
      def reformatDate(self, date: str) -> str:
          s = date.split()
          s.reverse()
          months = " JanFebMarAprMayJunJulAugSepOctNovDec"
          s[1] = str(months.index(s[1]) // 3 + 1).zfill(2)
          s[2] = s[2][:-2].zfill(2)
          return "-".join(s)
  
  

• func reformatDate(date string) string {
  	s := strings.Split(date, " ")
  	day, _ := strconv.Atoi(s[0][:len(s[0])-2])
  	months := " JanFebMarAprMayJunJulAugSepOctNovDec"
  	month := strings.Index(months, s[1])/3 + 1
  	year, _ := strconv.Atoi(s[2])
  	return fmt.Sprintf("%d-%02d-%02d", year, month, day)
  }
  

• function reformatDate(date: string): string {
      const s = date.split(' ');
      const months = ' JanFebMarAprMayJunJulAugSepOctNovDec';
      const day = parseInt(s[0].substring(0, s[0].length - 2));
      const month = Math.floor(months.indexOf(s[1]) / 3) + 1;
      return `${s[2]}-${month.toString().padStart(2, '0')}-${day.toString().padStart(2, '0')}`;
  }
  
  

• class Solution {
      /**
       * @param String $date
       * @return String
       */
      function reformatDate($date) {
          $arr = explode(' ', $date);
          $months = [
              'Jan' => '01',
              'Feb' => '02',
              'Mar' => '03',
              'Apr' => '04',
              'May' => '05',
              'Jun' => '06',
              'Jul' => '07',
              'Aug' => '08',
              'Sep' => '09',
              'Oct' => '10',
              'Nov' => '11',
              'Dec' => '12',
          ];
          $year = $arr[2];
          $month = $months[$arr[1]];
          $day = intval($arr[0]);
          if ($day > 0 && $day < 10) {
              $day = '0' . $day;
          }
          return $year . '-' . $month . '-' . $day;
      }
  }
  
  

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