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1479. Sales by Day of the Week
Description
Table: Orders
+---------------+---------+ | Column Name | Type | +---------------+---------+ | order_id | int | | customer_id | int | | order_date | date | | item_id | varchar | | quantity | int | +---------------+---------+ (ordered_id, item_id) is the primary key (combination of columns with unique values) for this table. This table contains information on the orders placed. order_date is the date item_id was ordered by the customer with id customer_id.
Table: Items
+---------------------+---------+ | Column Name | Type | +---------------------+---------+ | item_id | varchar | | item_name | varchar | | item_category | varchar | +---------------------+---------+ item_id is the primary key (column with unique values) for this table. item_name is the name of the item. item_category is the category of the item.
You are the business owner and would like to obtain a sales report for category items and the day of the week.
Write a solution to report how many units in each category have been ordered on each day of the week.
Return the result table ordered by category.
The result format is in the following example.
Example 1:
Input: Orders table: +------------+--------------+-------------+--------------+-------------+ | order_id | customer_id | order_date | item_id | quantity | +------------+--------------+-------------+--------------+-------------+ | 1 | 1 | 2020-06-01 | 1 | 10 | | 2 | 1 | 2020-06-08 | 2 | 10 | | 3 | 2 | 2020-06-02 | 1 | 5 | | 4 | 3 | 2020-06-03 | 3 | 5 | | 5 | 4 | 2020-06-04 | 4 | 1 | | 6 | 4 | 2020-06-05 | 5 | 5 | | 7 | 5 | 2020-06-05 | 1 | 10 | | 8 | 5 | 2020-06-14 | 4 | 5 | | 9 | 5 | 2020-06-21 | 3 | 5 | +------------+--------------+-------------+--------------+-------------+ Items table: +------------+----------------+---------------+ | item_id | item_name | item_category | +------------+----------------+---------------+ | 1 | LC Alg. Book | Book | | 2 | LC DB. Book | Book | | 3 | LC SmarthPhone | Phone | | 4 | LC Phone 2020 | Phone | | 5 | LC SmartGlass | Glasses | | 6 | LC T-Shirt XL | T-Shirt | +------------+----------------+---------------+ Output: +------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+ | Category | Monday | Tuesday | Wednesday | Thursday | Friday | Saturday | Sunday | +------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+ | Book | 20 | 5 | 0 | 0 | 10 | 0 | 0 | | Glasses | 0 | 0 | 0 | 0 | 5 | 0 | 0 | | Phone | 0 | 0 | 5 | 1 | 0 | 0 | 10 | | T-Shirt | 0 | 0 | 0 | 0 | 0 | 0 | 0 | +------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+ Explanation: On Monday (2020-06-01, 2020-06-08) were sold a total of 20 units (10 + 10) in the category Book (ids: 1, 2). On Tuesday (2020-06-02) were sold a total of 5 units in the category Book (ids: 1, 2). On Wednesday (2020-06-03) were sold a total of 5 units in the category Phone (ids: 3, 4). On Thursday (2020-06-04) were sold a total of 1 unit in the category Phone (ids: 3, 4). On Friday (2020-06-05) were sold 10 units in the category Book (ids: 1, 2) and 5 units in Glasses (ids: 5). On Saturday there are no items sold. On Sunday (2020-06-14, 2020-06-21) were sold a total of 10 units (5 +5) in the category Phone (ids: 3, 4). There are no sales of T-shirts.
Solutions
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# Write your MySQL query statement below SELECT item_category AS category, SUM(IF(DAYOFWEEK(order_date) = '2', quantity, 0)) AS Monday, SUM(IF(DAYOFWEEK(order_date) = '3', quantity, 0)) AS Tuesday, SUM(IF(DAYOFWEEK(order_date) = '4', quantity, 0)) AS Wednesday, SUM(IF(DAYOFWEEK(order_date) = '5', quantity, 0)) AS Thursday, SUM(IF(DAYOFWEEK(order_date) = '6', quantity, 0)) AS Friday, SUM(IF(DAYOFWEEK(order_date) = '7', quantity, 0)) AS Saturday, SUM(IF(DAYOFWEEK(order_date) = '1', quantity, 0)) AS Sunday FROM Orders AS o RIGHT JOIN Items AS i ON o.item_id = i.item_id GROUP BY category ORDER BY category;