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1470. Shuffle the Array

Description

Given the array nums consisting of 2n elements in the form [x1,x2,...,xn,y1,y2,...,yn].

Return the array in the form [x1,y1,x2,y2,...,xn,yn].

 

Example 1:

Input: nums = [2,5,1,3,4,7], n = 3
Output: [2,3,5,4,1,7] 
Explanation: Since x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 then the answer is [2,3,5,4,1,7].

Example 2:

Input: nums = [1,2,3,4,4,3,2,1], n = 4
Output: [1,4,2,3,3,2,4,1]

Example 3:

Input: nums = [1,1,2,2], n = 2
Output: [1,2,1,2]

 

Constraints:

  • 1 <= n <= 500
  • nums.length == 2n
  • 1 <= nums[i] <= 10^3

Solutions

  • class Solution {
        public int[] shuffle(int[] nums, int n) {
            int[] ans = new int[n << 1];
            for (int i = 0, j = 0; i < n; ++i) {
                ans[j++] = nums[i];
                ans[j++] = nums[i + n];
            }
            return ans;
        }
    }
    
  • class Solution {
    public:
        vector<int> shuffle(vector<int>& nums, int n) {
            vector<int> ans;
            for (int i = 0; i < n; ++i) {
                ans.push_back(nums[i]);
                ans.push_back(nums[i + n]);
            }
            return ans;
        }
    };
    
  • class Solution:
        def shuffle(self, nums: List[int], n: int) -> List[int]:
            ans = []
            for i in range(n):
                ans.append(nums[i])
                ans.append(nums[i + n])
            return ans
    
    
  • func shuffle(nums []int, n int) []int {
    	var ans []int
    	for i := 0; i < n; i++ {
    		ans = append(ans, nums[i])
    		ans = append(ans, nums[i+n])
    	}
    	return ans
    }
    
  • function shuffle(nums: number[], n: number): number[] {
        let ans = [];
        for (let i = 0; i < n; i++) {
            ans.push(nums[i], nums[n + i]);
        }
        return ans;
    }
    
    
  • impl Solution {
        pub fn shuffle(nums: Vec<i32>, n: i32) -> Vec<i32> {
            let n = n as usize;
            let mut res = Vec::new();
            for i in 0..n {
                res.push(nums[i]);
                res.push(nums[n + i]);
            }
            res
        }
    }
    
    

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