# 1455. Check If a Word Occurs As a Prefix of Any Word in a Sentence

## Description

Given a sentence that consists of some words separated by a single space, and a searchWord, check if searchWord is a prefix of any word in sentence.

Return the index of the word in sentence (1-indexed) where searchWord is a prefix of this word. If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.

A prefix of a string s is any leading contiguous substring of s.

Example 1:

Input: sentence = "i love eating burger", searchWord = "burg"
Output: 4
Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.


Example 2:

Input: sentence = "this problem is an easy problem", searchWord = "pro"
Output: 2
Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.


Example 3:

Input: sentence = "i am tired", searchWord = "you"
Output: -1
Explanation: "you" is not a prefix of any word in the sentence.


Constraints:

• 1 <= sentence.length <= 100
• 1 <= searchWord.length <= 10
• sentence consists of lowercase English letters and spaces.
• searchWord consists of lowercase English letters.

## Solutions

• class Solution {
public int isPrefixOfWord(String sentence, String searchWord) {
String[] words = sentence.split(" ");
for (int i = 0; i < words.length; ++i) {
if (words[i].startsWith(searchWord)) {
return i + 1;
}
}
return -1;
}
}

• class Solution {
public:
int isPrefixOfWord(string sentence, string searchWord) {
stringstream ss(sentence);
string s;
for (int i = 1; ss >> s; ++i) {
if (s.find(searchWord) == 0) {
return i;
}
}
return -1;
}
};

• class Solution:
def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
for i, s in enumerate(sentence.split(), 1):
if s.startswith(searchWord):
return i
return -1


• func isPrefixOfWord(sentence string, searchWord string) int {
for i, s := range strings.Split(sentence, " ") {
if strings.HasPrefix(s, searchWord) {
return i + 1
}
}
return -1
}

• function isPrefixOfWord(sentence: string, searchWord: string): number {
const ss = sentence.split(/\s/);
const n = ss.length;
for (let i = 0; i < n; i++) {
if (ss[i].startsWith(searchWord)) {
return i + 1;
}
}
return -1;
}


• class Solution {
/**
* @param String $sentence * @param String$searchWord
* @return Integer
*/
function isPrefixOfWord($sentence,$searchWord) {
$arr = explode(' ',$sentence);
for ($i = 0;$i < count($arr);$i++) {
if (strpos($arr[$i], $searchWord) === 0) { return$i + 1;
}
}
return -1;
}
}


• impl Solution {
pub fn is_prefix_of_word(sentence: String, search_word: String) -> i32 {
let ss = sentence.split_whitespace().collect::<Vec<&str>>();
for i in 0..ss.len() {
if ss[i].starts_with(&search_word) {
return (i + 1) as i32;
}
}
-1
}
}