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1431. Kids With the Greatest Number of Candies
Description
There are n
kids with candies. You are given an integer array candies
, where each candies[i]
represents the number of candies the ith
kid has, and an integer extraCandies
, denoting the number of extra candies that you have.
Return a boolean array result
of length n
, where result[i]
is true
if, after giving the ith
kid all the extraCandies
, they will have the greatest number of candies among all the kids, or false
otherwise.
Note that multiple kids can have the greatest number of candies.
Example 1:
Input: candies = [2,3,5,1,3], extraCandies = 3 Output: [true,true,true,false,true] Explanation: If you give all extraCandies to: - Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids. - Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids. - Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids. - Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids. - Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
Example 2:
Input: candies = [4,2,1,1,2], extraCandies = 1 Output: [true,false,false,false,false] Explanation: There is only 1 extra candy. Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.
Example 3:
Input: candies = [12,1,12], extraCandies = 10 Output: [true,false,true]
Constraints:
n == candies.length
2 <= n <= 100
1 <= candies[i] <= 100
1 <= extraCandies <= 50
Solutions
-
class Solution { public List<Boolean> kidsWithCandies(int[] candies, int extraCandies) { int mx = 0; for (int candy : candies) { mx = Math.max(mx, candy); } List<Boolean> res = new ArrayList<>(); for (int candy : candies) { res.add(candy + extraCandies >= mx); } return res; } }
-
class Solution { public: vector<bool> kidsWithCandies(vector<int>& candies, int extraCandies) { int mx = *max_element(candies.begin(), candies.end()); vector<bool> res; for (int candy : candies) { res.push_back(candy + extraCandies >= mx); } return res; } };
-
class Solution: def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]: mx = max(candies) return [candy + extraCandies >= mx for candy in candies]
-
func kidsWithCandies(candies []int, extraCandies int) (ans []bool) { mx := slices.Max(candies) for _, candy := range candies { ans = append(ans, candy+extraCandies >= mx) } return }
-
function kidsWithCandies(candies: number[], extraCandies: number): boolean[] { const max = candies.reduce((r, v) => Math.max(r, v)); return candies.map(v => v + extraCandies >= max); }
-
class Solution { /** * @param Integer[] $candies * @param Integer $extraCandies * @return Boolean[] */ function kidsWithCandies($candies, $extraCandies) { $max = max($candies); $rs = []; for ($i = 0; $i < count($candies); $i++) { array_push($rs, $candies[$i] + $extraCandies >= $max); } return $rs; } }
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impl Solution { pub fn kids_with_candies(candies: Vec<i32>, extra_candies: i32) -> Vec<bool> { let max = *candies.iter().max().unwrap(); candies .iter() .map(|v| v + extra_candies >= max) .collect() } }