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1347. Minimum Number of Steps to Make Two Strings Anagram

Description

You are given two strings of the same length s and t. In one step you can choose any character of t and replace it with another character.

Return the minimum number of steps to make t an anagram of s.

An Anagram of a string is a string that contains the same characters with a different (or the same) ordering.

 

Example 1:

Input: s = "bab", t = "aba"
Output: 1
Explanation: Replace the first 'a' in t with b, t = "bba" which is anagram of s.

Example 2:

Input: s = "leetcode", t = "practice"
Output: 5
Explanation: Replace 'p', 'r', 'a', 'i' and 'c' from t with proper characters to make t anagram of s.

Example 3:

Input: s = "anagram", t = "mangaar"
Output: 0
Explanation: "anagram" and "mangaar" are anagrams. 

 

Constraints:

• 1 <= s.length <= 5 * 104
• s.length == t.length
• s and t consist of lowercase English letters only.

Solutions

• Java
• C++
• Python
• Go
• Javascript
• TypeScript

• class Solution {
      public int minSteps(String s, String t) {
          int[] cnt = new int[26];
          for (int i = 0; i < s.length(); ++i) {
              ++cnt[s.charAt(i) - 'a'];
          }
          int ans = 0;
          for (int i = 0; i < t.length(); ++i) {
              if (--cnt[t.charAt(i) - 'a'] < 0) {
                  ++ans;
              }
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      int minSteps(string s, string t) {
          int cnt[26]{};
          for (char& c : s) ++cnt[c - 'a'];
          int ans = 0;
          for (char& c : t) {
              ans += --cnt[c - 'a'] < 0;
          }
          return ans;
      }
  };
  

• class Solution:
      def minSteps(self, s: str, t: str) -> int:
          cnt = Counter(s)
          ans = 0
          for c in t:
              if cnt[c] > 0:
                  cnt[c] -= 1
              else:
                  ans += 1
          return ans
  
  

• func minSteps(s string, t string) (ans int) {
  	cnt := [26]int{}
  	for _, c := range s {
  		cnt[c-'a']++
  	}
  	for _, c := range t {
  		cnt[c-'a']--
  		if cnt[c-'a'] < 0 {
  			ans++
  		}
  	}
  	return
  }
  

• /**
   * @param {string} s
   * @param {string} t
   * @return {number}
   */
  var minSteps = function (s, t) {
      const cnt = new Array(26).fill(0);
      for (const c of s) {
          const i = c.charCodeAt(0) - 'a'.charCodeAt(0);
          ++cnt[i];
      }
      let ans = 0;
      for (const c of t) {
          const i = c.charCodeAt(0) - 'a'.charCodeAt(0);
          ans += --cnt[i] < 0;
      }
      return ans;
  };
  
  

• function minSteps(s: string, t: string): number {
      const cnt: number[] = Array(26).fill(0);
      for (const c of s) {
          ++cnt[c.charCodeAt(0) - 97];
      }
      let ans = 0;
      for (const c of t) {
          if (--cnt[c.charCodeAt(0) - 97] < 0) {
              ++ans;
          }
      }
      return ans;
  }
  
  

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