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Formatted question description: https://leetcode.ca/all/1317.html

1317. Convert Integer to the Sum of Two No-Zero Integers (Easy)

Given an integer n. No-Zero integer is a positive integer which doesn't contain any 0 in its decimal representation.

Return a list of two integers [A, B] where:

  • A and B are No-Zero integers.
  • A + B = n

It's guarateed that there is at least one valid solution. If there are many valid solutions you can return any of them.

 

Example 1:

Input: n = 2
Output: [1,1]
Explanation: A = 1, B = 1. A + B = n and both A and B don't contain any 0 in their decimal representation.

Example 2:

Input: n = 11
Output: [2,9]

Example 3:

Input: n = 10000
Output: [1,9999]

Example 4:

Input: n = 69
Output: [1,68]

Example 5:

Input: n = 1010
Output: [11,999]

 

Constraints:

  • 2 <= n <= 10^4

Related Topics:
Math

Solution 1.

  • class Solution {
    public int[] getNoZeroIntegers(int n) {
        int[] nums = new int[2];
        int upper = n / 2;
        for (int i = 1; i <= upper; i++) {
            int num2 = n - i;
            if (noZero(i) && noZero(num2)) {
                nums[0] = i;
                nums[1] = num2;
                break;
            }
        }
        return nums;
    }

    public boolean noZero(int num) {
        if (num <= 0)
            return false;
        while (num > 0) {
            int remainder = num % 10;
            if (remainder == 0)
                return false;
            num /= 10;
        }
        return true;
    }
}

############

class Solution {
    public int[] getNoZeroIntegers(int n) {
        for (int a = 1;; ++a) {
            int b = n - a;
            if (!(a + "" + b).contains("0")) {
                return new int[] {a, b};
            }
        }
    }
}

  • // OJ: https://leetcode.com/problems/convert-integer-to-the-sum-of-two-no-zero-integers/
// Time: O(NlogN)
// Space: O(1)
class Solution {
    bool hasZero(int n) {
        for (; n; n /= 10) {
            if (n % 10 == 0) return true;
        }
        return false;
    }
public:
    vector<int> getNoZeroIntegers(int n) {
        int a = 1;
        for (; hasZero(a) || hasZero(n - a); ++a);
        return { a, n - a };
    }
};

  • class Solution:
    def getNoZeroIntegers(self, n: int) -> List[int]:
        for a in range(1, n):
            b = n - a
            if "0" not in str(a) + str(b):
                return [a, b]



  • func getNoZeroIntegers(n int) []int {
	for a := 1; ; a++ {
		b := n - a
		if !strings.Contains(strconv.Itoa(a)+strconv.Itoa(b), "0") {
			return []int{a, b}
		}
	}
}

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