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1317. Convert Integer to the Sum of Two No-Zero Integers

Description

No-Zero integer is a positive integer that does not contain any 0 in its decimal representation.

Given an integer n, return a list of two integers [a, b] where:

  • a and b are No-Zero integers.
  • a + b = n

The test cases are generated so that there is at least one valid solution. If there are many valid solutions, you can return any of them.

 

Example 1:

Input: n = 2
Output: [1,1]
Explanation: Let a = 1 and b = 1.
Both a and b are no-zero integers, and a + b = 2 = n.

Example 2:

Input: n = 11
Output: [2,9]
Explanation: Let a = 2 and b = 9.
Both a and b are no-zero integers, and a + b = 9 = n.
Note that there are other valid answers as [8, 3] that can be accepted.

 

Constraints:

  • 2 <= n <= 104

Solutions

  • class Solution {
    public int[] getNoZeroIntegers(int n) {
        for (int a = 1;; ++a) {
            int b = n - a;
            if (!(a + "" + b).contains("0")) {
                return new int[] {a, b};
            }
        }
    }
}

  • class Solution {
public:
    vector<int> getNoZeroIntegers(int n) {
        for (int a = 1;; ++a) {
            int b = n - a;
            if ((to_string(a) + to_string(b)).find('0') == -1) {
                return {a, b};
            }
        }
    }
};

  • class Solution:
    def getNoZeroIntegers(self, n: int) -> List[int]:
        for a in range(1, n):
            b = n - a
            if "0" not in str(a) + str(b):
                return [a, b]


  • func getNoZeroIntegers(n int) []int {
	for a := 1; ; a++ {
		b := n - a
		if !strings.Contains(strconv.Itoa(a)+strconv.Itoa(b), "0") {
			return []int{a, b}
		}
	}
}

  • function getNoZeroIntegers(n: number): number[] {
    for (let a = 1; ; ++a) {
        const b = n - a;
        if (!`${a}${b}`.includes('0')) {
            return [a, b];
        }
    }
}

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