Welcome to Subscribe On Youtube
1299. Replace Elements with Greatest Element on Right Side
Description
Given an array arr
, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1
.
After doing so, return the array.
Example 1:
Input: arr = [17,18,5,4,6,1] Output: [18,6,6,6,1,-1] Explanation: - index 0 --> the greatest element to the right of index 0 is index 1 (18). - index 1 --> the greatest element to the right of index 1 is index 4 (6). - index 2 --> the greatest element to the right of index 2 is index 4 (6). - index 3 --> the greatest element to the right of index 3 is index 4 (6). - index 4 --> the greatest element to the right of index 4 is index 5 (1). - index 5 --> there are no elements to the right of index 5, so we put -1.
Example 2:
Input: arr = [400] Output: [-1] Explanation: There are no elements to the right of index 0.
Constraints:
1 <= arr.length <= 104
1 <= arr[i] <= 105
Solutions
-
class Solution { public int[] replaceElements(int[] arr) { for (int i = arr.length - 1, max = -1; i >= 0; --i) { int t = arr[i]; arr[i] = max; max = Math.max(max, t); } return arr; } }
-
class Solution: def replaceElements(self, arr: List[int]) -> List[int]: m = -1 for i in range(len(arr) - 1, -1, -1): t = arr[i] arr[i] = m m = max(m, t) return arr
-
class Solution { public: vector<int> replaceElements(vector<int>& arr) { for (int i = arr.size() - 1, mx = -1; ~i; --i) { int x = arr[i]; arr[i] = mx; mx = max(mx, x); } return arr; } };
-
func replaceElements(arr []int) []int { for i, mx := len(arr)-1, -1; i >= 0; i-- { x := arr[i] arr[i] = mx mx = max(mx, x) } return arr }
-
function replaceElements(arr: number[]): number[] { for (let i = arr.length - 1, mx = -1; ~i; --i) { const x = arr[i]; arr[i] = mx; mx = Math.max(mx, x); } return arr; }