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Formatted question description: https://leetcode.ca/all/1267.html

# 1267. Count Servers that Communicate (Medium)

You are given a map of a server center, represented as a m * n integer matrix grid, where 1 means that on that cell there is a server and 0 means that it is no server. Two servers are said to communicate if they are on the same row or on the same column.

Return the number of servers that communicate with any other server.

Example 1: Input: grid = [[1,0],[0,1]]
Output: 0
Explanation: No servers can communicate with others.

Example 2: Input: grid = [[1,0],[1,1]]
Output: 3
Explanation: All three servers can communicate with at least one other server.


Example 3: Input: grid = [[1,1,0,0],[0,0,1,0],[0,0,1,0],[0,0,0,1]]
Output: 4
Explanation: The two servers in the first row can communicate with each other. The two servers in the third column can communicate with each other. The server at right bottom corner can't communicate with any other server.


Constraints:

• m == grid.length
• n == grid[i].length
• 1 <= m <= 250
• 1 <= n <= 250
• grid[i][j] == 0 or 1

Related Topics:
Array, Graph

## Solution 1.

• class Solution {
public int countServers(int[][] grid) {
if (grid == null || grid.length == 0 || grid.length == 0)
return 0;
int servers = 0;
int isolateServers = 0;
Map<Integer, List<Integer>> rowsMap = new HashMap<Integer, List<Integer>>();
Map<Integer, List<Integer>> columnsMap = new HashMap<Integer, List<Integer>>();
int rows = grid.length, columns = grid.length;
for (int i = 0; i < rows; i++) {
for (int j = 0; j < columns; j++) {
if (grid[i][j] == 1) {
servers++;
List<Integer> rowList = rowsMap.getOrDefault(i, new ArrayList<Integer>());
rowsMap.put(i, rowList);
List<Integer> columnList = columnsMap.getOrDefault(j, new ArrayList<Integer>());
columnsMap.put(j, columnList);
}
}
}
for (int i = 0; i < rows; i++) {
List<Integer> rowList = rowsMap.getOrDefault(i, new ArrayList<Integer>());
if (rowList.size() == 1) {
int column = rowList.get(0);
List<Integer> columnList = columnsMap.getOrDefault(column, new ArrayList<Integer>());
if (columnList.size() == 1)
isolateServers++;
}
}
int communicateServers = servers - isolateServers;
return communicateServers;
}
}

############

class Solution {
public int countServers(int[][] grid) {
int m = grid.length, n = grid.length;
int[] row = new int[m];
int[] col = new int[n];
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
if (grid[i][j] == 1) {
row[i]++;
col[j]++;
}
}
}
int ans = 0;
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
if (grid[i][j] == 1 && (row[i] > 1 || col[j] > 1)) {
++ans;
}
}
}
return ans;
}
}

• // OJ: https://leetcode.com/problems/count-servers-that-communicate/
// Time: O(MN)
// Space: O(M+N)
class Solution {
public:
int countServers(vector<vector<int>>& grid) {
int M = grid.size(), N = grid.size(), ans = 0;
vector<int> row(M, 0), col(N, 0);
for (int i = 0; i < M; ++i) {
for (int j = 0; j < N; ++j) {
row[i] += grid[i][j];
col[j] += grid[i][j];
}
}
for (int i = 0; i < M; ++i) {
for (int j = 0; j < N; ++j) {
if (grid[i][j] && (row[i] > 1 || col[j] > 1)) ++ans;
}
}
return ans;
}
};

• class Solution:
def countServers(self, grid: List[List[int]]) -> int:
m, n = len(grid), len(grid)
rows =  * m
cols =  * n
for i in range(m):
for j in range(n):
if grid[i][j] == 1:
rows[i] += 1
cols[j] += 1
res = 0
for i in range(m):
for j in range(n):
if grid[i][j] == 1:
if rows[i] > 1 or cols[j] > 1:
res += 1
return res

############

# 1267. Count Servers that Communicate
# https://leetcode.com/problems/count-servers-that-communicate/

class Solution:
def countServers(self, grid: List[List[int]]) -> int:
rows, cols = len(grid), len(grid)
rc, cc = Counter(), Counter()

for i in range(rows):
for j,c in enumerate(grid[i]):
if c == 1:
rc[i] += 1
cc[j] += 1

res = 0
for i in range(rows):
for j,c in enumerate(grid[i]):
if c == 1 and (rc[i] > 1 or cc[j] > 1):
res += 1

return res


• func countServers(grid [][]int) (ans int) {
m, n := len(grid), len(grid)
row, col := make([]int, m), make([]int, n)
for i := range grid {
for j, x := range grid[i] {
if x == 1 {
row[i]++
col[j]++
}
}
}
for i := range grid {
for j, x := range grid[i] {
if x == 1 && (row[i] > 1 || col[j] > 1) {
ans++
}
}
}
return
}

• function countServers(grid: number[][]): number {
const m = grid.length;
const n = grid.length;
const row = new Array(m).fill(0);
const col = new Array(n).fill(0);
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
if (grid[i][j] === 1) {
row[i]++;
col[j]++;
}
}
}
let ans = 0;
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
if (grid[i][j] === 1 && (row[i] > 1 || col[j] > 1)) {
ans++;
}
}
}
return ans;
}