Formatted question description: https://leetcode.ca/all/1171.html

# 1171. Remove Zero Sum Consecutive Nodes from Linked List

Medium

## Description

Given the head of a linked list, we repeatedly delete consecutive sequences of nodes that sum to 0 until there are no such sequences.

After doing so, return the head of the final linked list. You may return any such answer.

(Note that in the examples below, all sequences are serializations of ListNode objects.)

Example 1:

Input: head = [1,2,-3,3,1]

Output: [3,1]

Note: The answer [1,2,1] would also be accepted.

Example 2:

Input: head = [1,2,3,-3,4]

Output: [1,2,4]

Example 3:

Input: head = [1,2,3,-3,-2]

Output: 

Constraints:

• The given linked list will contain between 1 and 1000 nodes.
• Each node in the linked list has -1000 <= node.val <= 1000.

## Solution

Create a dummyHead and set dummyHead.next = head. Initialize temp = dummyHead. Each time delete zero sum consecutive nodes starting from temp.next. If there are nodes that are deleted, set temp.next to be the next node after deletion. Otherwise, set temp = temp.next.

Finally, return dummyHead.next.

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode removeZeroSumSublists(ListNode head) {
ListNode dummyHead = new ListNode(0);
ListNode temp = dummyHead;
while (temp != null) {
ListNode zeroLast = removeZero(temp.next);
if (zeroLast == null)
temp = temp.next;
else
temp.next = zeroLast.next;
}
}

public ListNode removeZero(ListNode node) {
ListNode temp = node;
int sum = 0;
while (temp != null) {
sum += temp.val;
if (sum == 0)
return temp;
else
temp = temp.next;
}
return null;
}
}