Formatted question description: https://leetcode.ca/all/1108.html

1108. Defanging an IP Address (Easy)

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

 

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

 

Constraints:

• The given address is a valid IPv4 address.

Related Topics:
String

Solution 1.

// OJ: https://leetcode.com/problems/defanging-an-ip-address/
// Time: O(N)
// Space: O(1)
class Solution {
public:
    string defangIPaddr(string address) {
        string ans;
        for (char c : address) {
            if (c == '.') ans += "[.]";
            else ans += c;
        }
        return ans;
    }
};

Java

• Java
• C++
• Python

• class Solution {
      public String defangIPaddr(String address) {
          address = address.replaceAll("\\.", "[\\.]");
          return address;
      }
  }
  

• // OJ: https://leetcode.com/problems/defanging-an-ip-address/
  // Time: O(N)
  // Space: O(1)
  class Solution {
  public:
      string defangIPaddr(string address) {
          string ans;
          for (char c : address) {
              if (c == '.') ans += "[.]";
              else ans += c;
          }
          return ans;
      }
  };
  

• # 1108. Defanging an IP Address
  # https://leetcode.com/problems/defanging-an-ip-address/
  
  class Solution:
      def defangIPaddr(self, address: str) -> str:
          address = address.replace('.', '[.]')
          
          return address
  
  

All Problems

All Solutions