Formatted question description: https://leetcode.ca/all/1108.html
1108. Defanging an IP Address (Easy)
Given a valid (IPv4) IP address
, return a defanged version of that IP address.
A defanged IP address replaces every period "."
with "[.]"
.
Example 1:
Input: address = "1.1.1.1" Output: "1[.]1[.]1[.]1"
Example 2:
Input: address = "255.100.50.0" Output: "255[.]100[.]50[.]0"
Constraints:
- The given
address
is a valid IPv4 address.
Related Topics:
String
Solution 1.
// OJ: https://leetcode.com/problems/defanging-an-ip-address/
// Time: O(N)
// Space: O(1)
class Solution {
public:
string defangIPaddr(string address) {
string ans;
for (char c : address) {
if (c == '.') ans += "[.]";
else ans += c;
}
return ans;
}
};
Java
-
class Solution { public String defangIPaddr(String address) { address = address.replaceAll("\\.", "[\\.]"); return address; } }
-
// OJ: https://leetcode.com/problems/defanging-an-ip-address/ // Time: O(N) // Space: O(1) class Solution { public: string defangIPaddr(string address) { string ans; for (char c : address) { if (c == '.') ans += "[.]"; else ans += c; } return ans; } };
-
# 1108. Defanging an IP Address # https://leetcode.com/problems/defanging-an-ip-address/ class Solution: def defangIPaddr(self, address: str) -> str: address = address.replace('.', '[.]') return address