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1037. Valid Boomerang

Description

Given an array points where points[i] = [xi, yi] represents a point on the X-Y plane, return true if these points are a boomerang.

A boomerang is a set of three points that are all distinct and not in a straight line.

 

Example 1:

Input: points = [[1,1],[2,3],[3,2]]
Output: true

Example 2:

Input: points = [[1,1],[2,2],[3,3]]
Output: false

 

Constraints:

• points.length == 3
• points[i].length == 2
• 0 <= xi, yi <= 100

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• RenderScript

• class Solution {
      public boolean isBoomerang(int[][] points) {
          int x1 = points[0][0], y1 = points[0][1];
          int x2 = points[1][0], y2 = points[1][1];
          int x3 = points[2][0], y3 = points[2][1];
          return (y2 - y1) * (x3 - x2) != (y3 - y2) * (x2 - x1);
      }
  }
  

• class Solution {
  public:
      bool isBoomerang(vector<vector<int>>& points) {
          int x1 = points[0][0], y1 = points[0][1];
          int x2 = points[1][0], y2 = points[1][1];
          int x3 = points[2][0], y3 = points[2][1];
          return (y2 - y1) * (x3 - x2) != (y3 - y2) * (x2 - x1);
      }
  };
  

• class Solution:
      def isBoomerang(self, points: List[List[int]]) -> bool:
          (x1, y1), (x2, y2), (x3, y3) = points
          return (y2 - y1) * (x3 - x2) != (y3 - y2) * (x2 - x1)
  
  

• func isBoomerang(points [][]int) bool {
  	x1, y1 := points[0][0], points[0][1]
  	x2, y2 := points[1][0], points[1][1]
  	x3, y3 := points[2][0], points[2][1]
  	return (y2-y1)*(x3-x2) != (y3-y2)*(x2-x1)
  }
  

• function isBoomerang(points: number[][]): boolean {
      const [x1, y1] = points[0];
      const [x2, y2] = points[1];
      const [x3, y3] = points[2];
      return (x1 - x2) * (y2 - y3) !== (x2 - x3) * (y1 - y2);
  }
  
  

• impl Solution {
      pub fn is_boomerang(points: Vec<Vec<i32>>) -> bool {
          let (x1, y1) = (points[0][0], points[0][1]);
          let (x2, y2) = (points[1][0], points[1][1]);
          let (x3, y3) = (points[2][0], points[2][1]);
          (x1 - x2) * (y2 - y3) != (x2 - x3) * (y1 - y2)
      }
  }
  
  

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