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1009. Complement of Base 10 Integer
Description
The complement of an integer is the integer you get when you flip all the 0
's to 1
's and all the 1
's to 0
's in its binary representation.
- For example, The integer
5
is"101"
in binary and its complement is"010"
which is the integer2
.
Given an integer n
, return its complement.
Example 1:
Input: n = 5 Output: 2 Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10.
Example 2:
Input: n = 7 Output: 0 Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10.
Example 3:
Input: n = 10 Output: 5 Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10.
Constraints:
0 <= n < 109
Note: This question is the same as 476: https://leetcode.com/problems/number-complement/
Solutions
-
class Solution { public int bitwiseComplement(int n) { if (n == 0) { return 1; } int ans = 0; boolean find = false; for (int i = 30; i >= 0; --i) { int b = n & (1 << i); if (!find && b == 0) { continue; } find = true; if (b == 0) { ans |= (1 << i); } } return ans; } }
-
class Solution { public: int bitwiseComplement(int n) { if (n == 0) return 1; int ans = 0; bool find = false; for (int i = 30; i >= 0; --i) { int b = n & (1 << i); if (!find && b == 0) continue; find = true; if (b == 0) ans |= (1 << i); } return ans; } };
-
class Solution: def bitwiseComplement(self, n: int) -> int: if n == 0: return 1 ans = 0 find = False for i in range(30, -1, -1): b = n & (1 << i) if not find and b == 0: continue find = True if b == 0: ans |= 1 << i return ans
-
func bitwiseComplement(n int) int { if n == 0 { return 1 } ans := 0 find := false for i := 30; i >= 0; i-- { b := n & (1 << i) if !find && b == 0 { continue } find = true if b == 0 { ans |= (1 << i) } } return ans }