Welcome to Subscribe On Youtube

984. String Without AAA or BBB

Description

Given two integers a and b, return any string s such that:

• s has length a + b and contains exactly a 'a' letters, and exactly b 'b' letters,
• The substring 'aaa' does not occur in s, and
• The substring 'bbb' does not occur in s.

 

Example 1:

Input: a = 1, b = 2
Output: "abb"
Explanation: "abb", "bab" and "bba" are all correct answers.

Example 2:

Input: a = 4, b = 1
Output: "aabaa"

 

Constraints:

• 0 <= a, b <= 100
• It is guaranteed such an s exists for the given a and b.

Solutions

• Java
• C++
• Python
• Go

• class Solution {
      public String strWithout3a3b(int a, int b) {
          StringBuilder ans = new StringBuilder();
          while (a > 0 && b > 0) {
              if (a > b) {
                  ans.append("aab");
                  a -= 2;
                  b -= 1;
              } else if (a < b) {
                  ans.append("bba");
                  a -= 1;
                  b -= 2;
              } else {
                  ans.append("ab");
                  --a;
                  --b;
              }
          }
          if (a > 0) {
              ans.append("a".repeat(a));
          }
          if (b > 0) {
              ans.append("b".repeat(b));
          }
          return ans.toString();
      }
  }
  

• class Solution {
  public:
      string strWithout3a3b(int a, int b) {
          string ans;
          while (a && b) {
              if (a > b) {
                  ans += "aab";
                  a -= 2;
                  b -= 1;
              } else if (a < b) {
                  ans += "bba";
                  a -= 1;
                  b -= 2;
              } else {
                  ans += "ab";
                  --a;
                  --b;
              }
          }
          if (a) ans += string(a, 'a');
          if (b) ans += string(b, 'b');
          return ans;
      }
  };
  

• class Solution:
      def strWithout3a3b(self, a: int, b: int) -> str:
          ans = []
          while a and b:
              if a > b:
                  ans.append('aab')
                  a, b = a - 2, b - 1
              elif a < b:
                  ans.append('bba')
                  a, b = a - 1, b - 2
              else:
                  ans.append('ab')
                  a, b = a - 1, b - 1
          if a:
              ans.append('a' * a)
          if b:
              ans.append('b' * b)
          return ''.join(ans)
  
  

• func strWithout3a3b(a int, b int) string {
  	var ans strings.Builder
  	for a > 0 && b > 0 {
  		if a > b {
  			ans.WriteString("aab")
  			a -= 2
  			b -= 1
  		} else if a < b {
  			ans.WriteString("bba")
  			a -= 1
  			b -= 2
  		} else {
  			ans.WriteString("ab")
  			a--
  			b--
  		}
  	}
  	if a > 0 {
  		ans.WriteString(strings.Repeat("a", a))
  	}
  	if b > 0 {
  		ans.WriteString(strings.Repeat("b", b))
  	}
  	return ans.String()
  }
  

All Problems

All Solutions