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981. Time Based Key-Value Store
Description
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
Implement the TimeMap
class:
TimeMap()
Initializes the object of the data structure.void set(String key, String value, int timestamp)
Stores the keykey
with the valuevalue
at the given timetimestamp
.String get(String key, int timestamp)
Returns a value such thatset
was called previously, withtimestamp_prev <= timestamp
. If there are multiple such values, it returns the value associated with the largesttimestamp_prev
. If there are no values, it returns""
.
Example 1:
Input ["TimeMap", "set", "get", "get", "set", "get", "get"] [[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]] Output [null, null, "bar", "bar", null, "bar2", "bar2"] Explanation TimeMap timeMap = new TimeMap(); timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1. timeMap.get("foo", 1); // return "bar" timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar". timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4. timeMap.get("foo", 4); // return "bar2" timeMap.get("foo", 5); // return "bar2"
Constraints:
1 <= key.length, value.length <= 100
key
andvalue
consist of lowercase English letters and digits.1 <= timestamp <= 107
- All the timestamps
timestamp
ofset
are strictly increasing. - At most
2 * 105
calls will be made toset
andget
.
Solutions
-
class TimeMap { private Map<String, TreeMap<Integer, String>> ktv = new HashMap<>(); public TimeMap() { } public void set(String key, String value, int timestamp) { ktv.computeIfAbsent(key, k -> new TreeMap<>()).put(timestamp, value); } public String get(String key, int timestamp) { if (!ktv.containsKey(key)) { return ""; } var tv = ktv.get(key); Integer t = tv.floorKey(timestamp); return t == null ? "" : tv.get(t); } } /** * Your TimeMap object will be instantiated and called as such: * TimeMap obj = new TimeMap(); * obj.set(key,value,timestamp); * String param_2 = obj.get(key,timestamp); */
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class TimeMap { public: TimeMap() { } void set(string key, string value, int timestamp) { ktv[key].emplace_back(timestamp, value); } string get(string key, int timestamp) { auto& pairs = ktv[key]; pair<int, string> p = {timestamp, string({127})}; auto i = upper_bound(pairs.begin(), pairs.end(), p); return i == pairs.begin() ? "" : (i - 1)->second; } private: unordered_map<string, vector<pair<int, string>>> ktv; }; /** * Your TimeMap object will be instantiated and called as such: * TimeMap* obj = new TimeMap(); * obj->set(key,value,timestamp); * string param_2 = obj->get(key,timestamp); */
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class TimeMap: def __init__(self): self.ktv = defaultdict(list) def set(self, key: str, value: str, timestamp: int) -> None: self.ktv[key].append((timestamp, value)) def get(self, key: str, timestamp: int) -> str: if key not in self.ktv: return '' tv = self.ktv[key] i = bisect_right(tv, (timestamp, chr(127))) return tv[i - 1][1] if i else '' # Your TimeMap object will be instantiated and called as such: # obj = TimeMap() # obj.set(key,value,timestamp) # param_2 = obj.get(key,timestamp)
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type TimeMap struct { ktv map[string][]pair } func Constructor() TimeMap { return TimeMap{map[string][]pair{} } } func (this *TimeMap) Set(key string, value string, timestamp int) { this.ktv[key] = append(this.ktv[key], pair{timestamp, value}) } func (this *TimeMap) Get(key string, timestamp int) string { pairs := this.ktv[key] i := sort.Search(len(pairs), func(i int) bool { return pairs[i].t > timestamp }) if i > 0 { return pairs[i-1].v } return "" } type pair struct { t int v string } /** * Your TimeMap object will be instantiated and called as such: * obj := Constructor(); * obj.Set(key,value,timestamp); * param_2 := obj.Get(key,timestamp); */