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937. Reorder Data in Log Files
Description
You are given an array of logs
. Each log is a space-delimited string of words, where the first word is the identifier.
There are two types of logs:
- Letter-logs: All words (except the identifier) consist of lowercase English letters.
- Digit-logs: All words (except the identifier) consist of digits.
Reorder these logs so that:
- The letter-logs come before all digit-logs.
- The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
- The digit-logs maintain their relative ordering.
Return the final order of the logs.
Example 1:
Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"] Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"] Explanation: The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig". The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".
Example 2:
Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"] Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]
Constraints:
1 <= logs.length <= 100
3 <= logs[i].length <= 100
- All the tokens of
logs[i]
are separated by a single space. logs[i]
is guaranteed to have an identifier and at least one word after the identifier.
Solutions
-
class Solution { public String[] reorderLogFiles(String[] logs) { Arrays.sort(logs, this::cmp); return logs; } private int cmp(String a, String b) { String[] t1 = a.split(" ", 2); String[] t2 = b.split(" ", 2); boolean d1 = Character.isDigit(t1[1].charAt(0)); boolean d2 = Character.isDigit(t2[1].charAt(0)); if (!d1 && !d2) { int v = t1[1].compareTo(t2[1]); return v == 0 ? t1[0].compareTo(t2[0]) : v; } if (d1 && d2) { return 0; } return d1 ? 1 : -1; } }
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class Solution: def reorderLogFiles(self, logs: List[str]) -> List[str]: def cmp(x): a, b = x.split(' ', 1) return (0, b, a) if b[0].isalpha() else (1,) return sorted(logs, key=cmp)
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function reorderLogFiles(logs: string[]): string[] { const isDigit = (c: string) => c >= '0' && c <= '9'; return logs.sort((a, b) => { const end1 = a[a.length - 1]; const end2 = b[b.length - 1]; if (isDigit(end1) && isDigit(end2)) { return 0; } if (isDigit(end1)) { return 1; } if (isDigit(end2)) { return -1; } const content1 = a.split(' ').slice(1).join(' '); const content2 = b.split(' ').slice(1).join(' '); if (content1 === content2) { return a < b ? -1 : 1; } return content1 < content2 ? -1 : 1; }); }
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impl Solution { pub fn reorder_log_files(mut logs: Vec<String>) -> Vec<String> { logs.sort_by(|s1, s2| { let (start1, content1) = s1.split_once(' ').unwrap(); let (start2, content2) = s2.split_once(' ').unwrap(); match ( content1.chars().nth(0).unwrap().is_digit(10), content2.chars().nth(0).unwrap().is_digit(10), ) { (true, true) => std::cmp::Ordering::Equal, (true, false) => std::cmp::Ordering::Greater, (false, true) => std::cmp::Ordering::Less, (false, false) => content1.cmp(&content2).then(start1.cmp(&start2)), } }); logs } }
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class Solution { public: vector<string> reorderLogFiles(vector<string>& logs) { stable_sort(logs.begin(), logs.end(), [](const string& log1, const string& log2) { int idx1 = log1.find(' '); int idx2 = log2.find(' '); string id1 = log1.substr(0, idx1); string id2 = log2.substr(0, idx2); string content1 = log1.substr(idx1 + 1); string content2 = log2.substr(idx2 + 1); bool isLetter1 = isalpha(content1[0]); bool isLetter2 = isalpha(content2[0]); if (isLetter1 && isLetter2) { if (content1 != content2) { return content1 < content2; } return id1 < id2; } return isLetter1 > isLetter2; }); return logs; } };
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func reorderLogFiles(logs []string) []string { sort.SliceStable(logs, func(i, j int) bool { log1, log2 := logs[i], logs[j] idx1 := strings.IndexByte(log1, ' ') idx2 := strings.IndexByte(log2, ' ') id1, content1 := log1[:idx1], log1[idx1+1:] id2, content2 := log2[:idx2], log2[idx2+1:] isLetter1 := 'a' <= content1[0] && content1[0] <= 'z' isLetter2 := 'a' <= content2[0] && content2[0] <= 'z' if isLetter1 && isLetter2 { if content1 != content2 { return content1 < content2 } return id1 < id2 } return isLetter1 && !isLetter2 }) return logs }