Welcome to Subscribe On Youtube

777. Swap Adjacent in LR String

Description

In a string composed of 'L', 'R', and 'X' characters, like "RXXLRXRXL", a move consists of either replacing one occurrence of "XL" with "LX", or replacing one occurrence of "RX" with "XR". Given the starting string start and the ending string end, return True if and only if there exists a sequence of moves to transform one string to the other.

 

Example 1:

Input: start = "RXXLRXRXL", end = "XRLXXRRLX"
Output: true
Explanation: We can transform start to end following these steps:
RXXLRXRXL ->
XRXLRXRXL ->
XRLXRXRXL ->
XRLXXRRXL ->
XRLXXRRLX

Example 2:

Input: start = "X", end = "L"
Output: false

 

Constraints:

  • 1 <= start.length <= 104
  • start.length == end.length
  • Both start and end will only consist of characters in 'L', 'R', and 'X'.

Solutions

  • class Solution {
    public boolean canTransform(String start, String end) {
        int n = start.length();
        int i = 0, j = 0;
        while (true) {
            while (i < n && start.charAt(i) == 'X') {
                ++i;
            }
            while (j < n && end.charAt(j) == 'X') {
                ++j;
            }
            if (i == n && j == n) {
                return true;
            }
            if (i == n || j == n || start.charAt(i) != end.charAt(j)) {
                return false;
            }
            if (start.charAt(i) == 'L' && i < j || start.charAt(i) == 'R' && i > j) {
                return false;
            }
            ++i;
            ++j;
        }
    }
}

  • class Solution {
public:
    bool canTransform(string start, string end) {
        int n = start.size();
        int i = 0, j = 0;
        while (true) {
            while (i < n && start[i] == 'X') ++i;
            while (j < n && end[j] == 'X') ++j;
            if (i == n && j == n) return true;
            if (i == n || j == n || start[i] != end[j]) return false;
            if (start[i] == 'L' && i < j) return false;
            if (start[i] == 'R' && i > j) return false;
            ++i;
            ++j;
        }
    }
};

  • class Solution:
    def canTransform(self, start: str, end: str) -> bool:
        n = len(start)
        i = j = 0
        while 1:
            while i < n and start[i] == 'X':
                i += 1
            while j < n and end[j] == 'X':
                j += 1
            if i >= n and j >= n:
                return True
            if i >= n or j >= n or start[i] != end[j]:
                return False
            if start[i] == 'L' and i < j:
                return False
            if start[i] == 'R' and i > j:
                return False
            i, j = i + 1, j + 1


  • func canTransform(start string, end string) bool {
	n := len(start)
	i, j := 0, 0
	for {
		for i < n && start[i] == 'X' {
			i++
		}
		for j < n && end[j] == 'X' {
			j++
		}
		if i == n && j == n {
			return true
		}
		if i == n || j == n || start[i] != end[j] {
			return false
		}
		if start[i] == 'L' && i < j {
			return false
		}
		if start[i] == 'R' && i > j {
			return false
		}
		i, j = i+1, j+1
	}
}

All Problems

All Solutions