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710. Random Pick with Blacklist
Description
You are given an integer n
and an array of unique integers blacklist
. Design an algorithm to pick a random integer in the range [0, n - 1]
that is not in blacklist
. Any integer that is in the mentioned range and not in blacklist
should be equally likely to be returned.
Optimize your algorithm such that it minimizes the number of calls to the built-in random function of your language.
Implement the Solution
class:
Solution(int n, int[] blacklist)
Initializes the object with the integern
and the blacklisted integersblacklist
.int pick()
Returns a random integer in the range[0, n - 1]
and not inblacklist
.
Example 1:
Input ["Solution", "pick", "pick", "pick", "pick", "pick", "pick", "pick"] [[7, [2, 3, 5]], [], [], [], [], [], [], []] Output [null, 0, 4, 1, 6, 1, 0, 4] Explanation Solution solution = new Solution(7, [2, 3, 5]); solution.pick(); // return 0, any integer from [0,1,4,6] should be ok. Note that for every call of pick, // 0, 1, 4, and 6 must be equally likely to be returned (i.e., with probability 1/4). solution.pick(); // return 4 solution.pick(); // return 1 solution.pick(); // return 6 solution.pick(); // return 1 solution.pick(); // return 0 solution.pick(); // return 4
Constraints:
1 <= n <= 109
0 <= blacklist.length <= min(105, n - 1)
0 <= blacklist[i] < n
- All the values of
blacklist
are unique. - At most
2 * 104
calls will be made topick
.
Solutions
-
class Solution { private Map<Integer, Integer> d = new HashMap<>(); private Random rand = new Random(); private int k; public Solution(int n, int[] blacklist) { k = n - blacklist.length; int i = k; Set<Integer> black = new HashSet<>(); for (int b : blacklist) { black.add(b); } for (int b : blacklist) { if (b < k) { while (black.contains(i)) { ++i; } d.put(b, i++); } } } public int pick() { int x = rand.nextInt(k); return d.getOrDefault(x, x); } } /** * Your Solution object will be instantiated and called as such: * Solution obj = new Solution(n, blacklist); * int param_1 = obj.pick(); */
-
class Solution { public: unordered_map<int, int> d; int k; Solution(int n, vector<int>& blacklist) { k = n - blacklist.size(); int i = k; unordered_set<int> black(blacklist.begin(), blacklist.end()); for (int& b : blacklist) { if (b < k) { while (black.count(i)) ++i; d[b] = i++; } } } int pick() { int x = rand() % k; return d.count(x) ? d[x] : x; } }; /** * Your Solution object will be instantiated and called as such: * Solution* obj = new Solution(n, blacklist); * int param_1 = obj->pick(); */
-
class Solution: def __init__(self, n: int, blacklist: List[int]): self.k = n - len(blacklist) self.d = {} i = self.k black = set(blacklist) for b in blacklist: if b < self.k: while i in black: i += 1 self.d[b] = i i += 1 def pick(self) -> int: x = randrange(self.k) return self.d.get(x, x) # Your Solution object will be instantiated and called as such: # obj = Solution(n, blacklist) # param_1 = obj.pick()
-
type Solution struct { d map[int]int k int } func Constructor(n int, blacklist []int) Solution { k := n - len(blacklist) i := k black := map[int]bool{} for _, b := range blacklist { black[b] = true } d := map[int]int{} for _, b := range blacklist { if b < k { for black[i] { i++ } d[b] = i i++ } } return Solution{d, k} } func (this *Solution) Pick() int { x := rand.Intn(this.k) if v, ok := this.d[x]; ok { return v } return x } /** * Your Solution object will be instantiated and called as such: * obj := Constructor(n, blacklist); * param_1 := obj.Pick(); */