703. Kth Largest Element in a Stream

Description

Design a class to find the k^th largest element in a stream. Note that it is the k^th largest element in the sorted order, not the k^th distinct element.

Implement KthLargest class:

KthLargest(int k, int[] nums) Initializes the object with the integer k and the stream of integers nums.
int add(int val) Appends the integer val to the stream and returns the element representing the k^th largest element in the stream.

Example 1:

Input
["KthLargest", "add", "add", "add", "add", "add"]
[[3, [4, 5, 8, 2]], [3], [5], [10], [9], [4]]
Output
[null, 4, 5, 5, 8, 8]

Explanation
KthLargest kthLargest = new KthLargest(3, [4, 5, 8, 2]);
kthLargest.add(3);   // return 4
kthLargest.add(5);   // return 5
kthLargest.add(10);  // return 5
kthLargest.add(9);   // return 8
kthLargest.add(4);   // return 8

Constraints:

1 <= k <= 10⁴
0 <= nums.length <= 10⁴
-10⁴ <= nums[i] <= 10⁴
-10⁴ <= val <= 10⁴
At most 10⁴ calls will be made to add.
It is guaranteed that there will be at least k elements in the array when you search for the k^th element.

Solutions

class KthLargest {
    private PriorityQueue<Integer> q;
    private int size;

    public KthLargest(int k, int[] nums) {
        q = new PriorityQueue<>(k);
        size = k;
        for (int num : nums) {
            add(num);
        }
    }

    public int add(int val) {
        q.offer(val);
        if (q.size() > size) {
            q.poll();
        }
        return q.peek();
    }
}

/**
 * Your KthLargest object will be instantiated and called as such:
 * KthLargest obj = new KthLargest(k, nums);
 * int param_1 = obj.add(val);
 */

class KthLargest {
public:
    priority_queue<int, vector<int>, greater<int>> q;
    int size;

    KthLargest(int k, vector<int>& nums) {
        size = k;
        for (int num : nums) add(num);
    }

    int add(int val) {
        q.push(val);
        if (q.size() > size) q.pop();
        return q.top();
    }
};

/**
 * Your KthLargest object will be instantiated and called as such:
 * KthLargest* obj = new KthLargest(k, nums);
 * int param_1 = obj->add(val);
 */

class KthLargest:
    def __init__(self, k: int, nums: List[int]):
        self.q = []
        self.size = k
        for num in nums:
            self.add(num)

    def add(self, val: int) -> int:
        heappush(self.q, val)
        if len(self.q) > self.size:
            heappop(self.q)
        return self.q[0]


# Your KthLargest object will be instantiated and called as such:
# obj = KthLargest(k, nums)
# param_1 = obj.add(val)

type KthLargest struct {
	h *IntHeap
	k int
}

func Constructor(k int, nums []int) KthLargest {
	h := &IntHeap{}
	heap.Init(h)
	for _, v := range nums {
		heap.Push(h, v)
	}

	for h.Len() > k {
		heap.Pop(h)
	}

	return KthLargest{
		h: h,
		k: k,
	}
}

func (this *KthLargest) Add(val int) int {
	heap.Push(this.h, val)
	for this.h.Len() > this.k {
		heap.Pop(this.h)
	}

	return this.h.Top()
}

func connectSticks(sticks []int) int {
	h := IntHeap(sticks)
	heap.Init(&h)
	res := 0
	for h.Len() > 1 {
		val := heap.Pop(&h).(int)
		val += heap.Pop(&h).(int)
		res += val
		heap.Push(&h, val)
	}
	return res
}

type IntHeap []int

func (h IntHeap) Len() int           { return len(h) }
func (h IntHeap) Less(i, j int) bool { return h[i] < h[j] }
func (h IntHeap) Swap(i, j int)      { h[i], h[j] = h[j], h[i] }
func (h *IntHeap) Push(x any) {
	*h = append(*h, x.(int))
}
func (h *IntHeap) Pop() any {
	old := *h
	n := len(old)
	x := old[n-1]
	*h = old[0 : n-1]
	return x
}

func (h *IntHeap) Top() int {
	if (*h).Len() == 0 {
		return 0
	}

	return (*h)[0]
}

/**
 * Your KthLargest object will be instantiated and called as such:
 * obj := Constructor(k, nums);
 * param_1 := obj.Add(val);
 */

/**
 * @param {number} k
 * @param {number[]} nums
 */
var KthLargest = function (k, nums) {
    this.k = k;
    this.heap = new MinHeap();
    for (let num of nums) {
        this.add(num);
    }
};

/**
 * @param {number} val
 * @return {number}
 */
KthLargest.prototype.add = function (val) {
    this.heap.offer(val);
    if (this.heap.size() > this.k) {
        this.heap.poll();
    }
    return this.heap.peek();
};

class MinHeap {
    constructor(data = []) {
        this.data = data;
        this.comparator = (a, b) => a - b;
        this.heapify();
    }

    heapify() {
        if (this.size() < 2) return;
        for (let i = 1; i < this.size(); i++) {
            this.bubbleUp(i);
        }
    }

    peek() {
        if (this.size() === 0) return null;
        return this.data[0];
    }

    offer(value) {
        this.data.push(value);
        this.bubbleUp(this.size() - 1);
    }

    poll() {
        if (this.size() === 0) {
            return null;
        }
        const result = this.data[0];
        const last = this.data.pop();
        if (this.size() !== 0) {
            this.data[0] = last;
            this.bubbleDown(0);
        }
        return result;
    }

    bubbleUp(index) {
        while (index > 0) {
            const parentIndex = (index - 1) >> 1;
            if (this.comparator(this.data[index], this.data[parentIndex]) < 0) {
                this.swap(index, parentIndex);
                index = parentIndex;
            } else {
                break;
            }
        }
    }

    bubbleDown(index) {
        const lastIndex = this.size() - 1;
        while (true) {
            const leftIndex = index * 2 + 1;
            const rightIndex = index * 2 + 2;
            let findIndex = index;
            if (
                leftIndex <= lastIndex &&
                this.comparator(this.data[leftIndex], this.data[findIndex]) < 0
            ) {
                findIndex = leftIndex;
            }
            if (
                rightIndex <= lastIndex &&
                this.comparator(this.data[rightIndex], this.data[findIndex]) < 0
            ) {
                findIndex = rightIndex;
            }
            if (index !== findIndex) {
                this.swap(index, findIndex);
                index = findIndex;
            } else {
                break;
            }
        }
    }

    swap(index1, index2) {
        [this.data[index1], this.data[index2]] = [this.data[index2], this.data[index1]];
    }

    size() {
        return this.data.length;
    }
}

/**
 * Your KthLargest object will be instantiated and called as such:
 * var obj = new KthLargest(k, nums)
 * var param_1 = obj.add(val)
 */

703 - Kth Largest Element in a Stream

703. Kth Largest Element in a Stream

Description

Solutions

All Problems

All Solutions

Welcome to Subscribe On Youtube

703. Kth Largest Element in a Stream

Description

Solutions

All Problems

All Solutions