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Formatted question description: https://leetcode.ca/all/571.html

# 571. Find Median Given Frequency of Numbers

## Level

Hard

## Description

The `Numbers`

table keeps the value of number and its frequency.

```
+----------+-------------+
| Number | Frequency |
+----------+-------------|
| 0 | 7 |
| 1 | 1 |
| 2 | 3 |
| 3 | 1 |
+----------+-------------+
```

In this table, the numbers are `0, 0, 0, 0, 0, 0, 0, 1, 2, 2, 2, 3`

, so the median is `(0 + 0) / 2 = 0`

.

```
+--------+
| median |
+--------|
| 0.0000 |
+--------+
```

Write a query to find the median of all numbers and name the result as `median`

.

## Solution

Suppose `n1.Number`

is the median in table `Numbers`

. Then the count of numbers less than or equal to `n1.Number`

should be at least half of the total counts, and the count of numbers less than `n1.Number`

should be at most half of the total counts.

```
# Write your MySQL query statement below
select avg(Number) as median from (
select n1.Number from Numbers n1 join Numbers n2 on n1.Number >= n2.Number
group by n1.Number
having
sum(n2.Frequency) >= (select sum(Frequency) from Numbers) / 2
and
sum(n2.Frequency) - avg(n1.Frequency) <= (select sum(Frequency) from Numbers) / 2
) med;
```