231. Power of Two

Description

Given an integer n, return true if it is a power of two. Otherwise, return false.

An integer n is a power of two, if there exists an integer x such that n == 2^x.

Example 1:

Input: n = 1
Output: true
Explanation: 2⁰ = 1

Example 2:

Input: n = 16
Output: true
Explanation: 2⁴ = 16

Example 3:

Input: n = 3
Output: false

Constraints:

Follow up: Could you solve it without loops/recursion?

class Solution {
    public boolean isPowerOfTwo(int n) {
        return n > 0 && (n & (n - 1)) == 0;
    }
}

class Solution {
public:
    bool isPowerOfTwo(int n) {
        return n > 0 && (n & (n - 1)) == 0;
    }
};

class Solution:
    def isPowerOfTwo(self, n: int) -> bool:
        return n > 0 and (n & (n - 1)) == 0

func isPowerOfTwo(n int) bool {
	return n > 0 && (n&(n-1)) == 0
}

function isPowerOfTwo(n: number): boolean {
    return n > 0 && (n & (n - 1)) === 0;
}

/**
 * @param {number} n
 * @return {boolean}
 */
var isPowerOfTwo = function (n) {
    return n > 0 && (n & (n - 1)) == 0;
};

impl Solution {
    pub fn is_power_of_two(n: i32) -> bool {
        n > 0 && (n & (n - 1)) == 0
    }
}