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231. Power of Two
Description
Given an integer n
, return true
if it is a power of two. Otherwise, return false
.
An integer n
is a power of two, if there exists an integer x
such that n == 2x
.
Example 1:
Input: n = 1 Output: true Explanation: 20 = 1
Example 2:
Input: n = 16 Output: true Explanation: 24 = 16
Example 3:
Input: n = 3 Output: false
Constraints:
-231 <= n <= 231 - 1
Follow up: Could you solve it without loops/recursion?
Solutions
-
class Solution { public boolean isPowerOfTwo(int n) { return n > 0 && (n & (n - 1)) == 0; } }
-
class Solution { public: bool isPowerOfTwo(int n) { return n > 0 && (n & (n - 1)) == 0; } };
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class Solution: def isPowerOfTwo(self, n: int) -> bool: return n > 0 and (n & (n - 1)) == 0
-
func isPowerOfTwo(n int) bool { return n > 0 && (n&(n-1)) == 0 }
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function isPowerOfTwo(n: number): boolean { return n > 0 && (n & (n - 1)) === 0; }
-
/** * @param {number} n * @return {boolean} */ var isPowerOfTwo = function (n) { return n > 0 && (n & (n - 1)) == 0; };