227. Basic Calculator II

Description

Given a string s which represents an expression, evaluate this expression and return its value.

The integer division should truncate toward zero.

You may assume that the given expression is always valid. All intermediate results will be in the range of [-2³¹, 2³¹ - 1].

Note: You are not allowed to use any built-in function which evaluates strings as mathematical expressions, such as eval().

Example 1:

Input: s = "3+2*2"
Output: 7

Example 2:

Input: s = " 3/2 "
Output: 1

Example 3:

Input: s = " 3+5 / 2 "
Output: 5

Constraints:

1 <= s.length <= 3 * 10⁵
s consists of integers and operators ('+', '-', '*', '/') separated by some number of spaces.
s represents a valid expression.
All the integers in the expression are non-negative integers in the range [0, 2³¹ - 1].
The answer is guaranteed to fit in a 32-bit integer.

Solutions

Solution 1: Stack

We traverse the string $s$, and use a variable sign to record the operator before each number. For the first number, its previous operator is considered as a plus sign. Each time we traverse to the end of a number, we decide the calculation method based on sign:

Plus sign: push the number into the stack;
Minus sign: push the opposite number into the stack;
Multiplication and division signs: calculate the number with the top element of the stack, and replace the top element of the stack with the calculation result.

After the traversal ends, the sum of the elements in the stack is the answer.

The time complexity is $O(n)$, and the space complexity is $O(n)$, where $n$ is the length of the string $s$.

class Solution {
    public int calculate(String s) {
        Deque<Integer> stk = new ArrayDeque<>();
        char sign = '+';
        int v = 0;
        for (int i = 0; i < s.length(); ++i) {
            char c = s.charAt(i);
            if (Character.isDigit(c)) {
                v = v * 10 + (c - '0');
            }
            if (i == s.length() - 1 || c == '+' || c == '-' || c == '*' || c == '/') {
                if (sign == '+') {
                    stk.push(v);
                } else if (sign == '-') {
                    stk.push(-v);
                } else if (sign == '*') {
                    stk.push(stk.pop() * v);
                } else {
                    stk.push(stk.pop() / v);
                }
                sign = c;
                v = 0;
            }
        }
        int ans = 0;
        while (!stk.isEmpty()) {
            ans += stk.pop();
        }
        return ans;
    }
}

class Solution {
public:
    int calculate(string s) {
        int v = 0, n = s.size();
        char sign = '+';
        stack<int> stk;
        for (int i = 0; i < n; ++i) {
            char c = s[i];
            if (isdigit(c)) v = v * 10 + (c - '0');
            if (i == n - 1 || c == '+' || c == '-' || c == '*' || c == '/') {
                if (sign == '+')
                    stk.push(v);
                else if (sign == '-')
                    stk.push(-v);
                else if (sign == '*') {
                    int t = stk.top();
                    stk.pop();
                    stk.push(t * v);
                } else {
                    int t = stk.top();
                    stk.pop();
                    stk.push(t / v);
                }
                sign = c;
                v = 0;
            }
        }
        int ans = 0;
        while (!stk.empty()) {
            ans += stk.top();
            stk.pop();
        }
        return ans;
    }
};

class Solution:
    def calculate(self, s: str) -> int:
        v, n = 0, len(s)
        sign = '+'
        stk = []
        for i, c in enumerate(s):
            if c.isdigit():
                v = v * 10 + int(c)
            if i == n - 1 or c in '+-*/':
                if sign == '+':
                    stk.append(v)
                # for "10-2*5": when '-' encountered, var 'sign' is still '+'
                # so '10' will be pushed to stk before setting sign to '-'
                elif sign == '-':
                    stk.append(-v)
                elif sign == '*':
                    stk.append(stk.pop() * v)
                elif sign == '/':
                    stk.append(int(stk.pop() / v))
                else:
                    print("operator not supported")

                sign = c # reset inside 'if'
                v = 0
        return sum(stk)

func calculate(s string) int {
	sign := '+'
	stk := []int{}
	v := 0
	for i, c := range s {
		digit := '0' <= c && c <= '9'
		if digit {
			v = v*10 + int(c-'0')
		}
		if i == len(s)-1 || !digit && c != ' ' {
			switch sign {
			case '+':
				stk = append(stk, v)
			case '-':
				stk = append(stk, -v)
			case '*':
				stk[len(stk)-1] *= v
			case '/':
				stk[len(stk)-1] /= v
			}
			sign = c
			v = 0
		}
	}
	ans := 0
	for _, v := range stk {
		ans += v
	}
	return ans
}

using System.Collections.Generic;
using System.Linq;

struct Element
{
    public char Op;
    public int Number;
    public Element(char op, int number)
    {
        Op = op;
        Number = number;
    }
}

public class Solution {
    public int Calculate(string s) {
        var stack = new Stack<Element>();
        var readingNumber = false;
        var number = 0;
        var op = '+';
        foreach (var ch in ((IEnumerable<char>)s).Concat(Enumerable.Repeat('+', 1)))
        {
            if (ch >= '0' && ch <= '9')
            {
                if (!readingNumber)
                {
                    readingNumber = true;
                    number = 0;
                }
                number = (number * 10) + (ch - '0');
            }
            else if (ch != ' ')
            {
                readingNumber = false;
                if (op == '+' || op == '-')
                {
                    if (stack.Count == 2)
                    {
                        var prev = stack.Pop();
                        var first = stack.Pop();
                        if (prev.Op == '+')
                        {
                            stack.Push(new Element(first.Op, first.Number + prev.Number));
                        }
                        else // '-'
                        {
                            stack.Push(new Element(first.Op, first.Number - prev.Number));
                        }
                    }
                    stack.Push(new Element(op, number));
                }
                else
                {
                    var prev = stack.Pop();
                    if (op == '*')
                    {
                        stack.Push(new Element(prev.Op, prev.Number * number));
                    }
                    else // '/'
                    {
                        stack.Push(new Element(prev.Op, prev.Number / number));
                    }
                }
                op = ch; 
            }
        }
        
        if (stack.Count == 2)
        {
            var second = stack.Pop();
            var first = stack.Pop();
            if (second.Op == '+')
            {
                stack.Push(new Element(first.Op, first.Number + second.Number));
            }
            else // '-'
            {
                stack.Push(new Element(first.Op, first.Number - second.Number));
            }
        }
        
        return stack.Peek().Number;
    }
}

227 - Basic Calculator II

227. Basic Calculator II

Description

Solutions

All Problems

All Solutions

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227. Basic Calculator II

Description

Solutions

All Problems

All Solutions