In an election, the i
-th vote was cast for persons[i]
at time
times[i]
.
Now, we would like to implement the following query function: TopVotedCandidate.q(int
t)
will return the number of the person that was leading the election at time
t
.
Votes cast at time t
will count towards our query. In the case of a tie,
the most recent vote (among tied candidates) wins.
Example 1:
Input: ["TopVotedCandidate","q","q","q","q","q","q"], [[[0,1,1,0,0,1,0],[0,5,10,15,20,25,30]],[3],[12],[25],[15],[24],[8]] Output: [null,0,1,1,0,0,1] Explanation: At time 3, the votes are [0], and 0 is leading. At time 12, the votes are [0,1,1], and 1 is leading. At time 25, the votes are [0,1,1,0,0,1], and 1 is leading (as ties go to the most recent vote.) This continues for 3 more queries at time 15, 24, and 8.
Note:
1 <= persons.length = times.length <= 5000
0 <= persons[i] <= persons.length
times
is a strictly increasing array with all elements in [0,
10^9]
.
TopVotedCandidate.q
is called at most 10000
times per test
case.
TopVotedCandidate.q(int t)
is always called with t >=
times[0]
.