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911. Online Election

Description

You are given two integer arrays persons and times. In an election, the ith vote was cast for persons[i] at time times[i].

For each query at a time t, find the person that was leading the election at time t. Votes cast at time t will count towards our query. In the case of a tie, the most recent vote (among tied candidates) wins.

Implement the TopVotedCandidate class:

  • TopVotedCandidate(int[] persons, int[] times) Initializes the object with the persons and times arrays.
  • int q(int t) Returns the number of the person that was leading the election at time t according to the mentioned rules.

 

Example 1:

Input
["TopVotedCandidate", "q", "q", "q", "q", "q", "q"]
[[[0, 1, 1, 0, 0, 1, 0], [0, 5, 10, 15, 20, 25, 30]], [3], [12], [25], [15], [24], [8]]
Output
[null, 0, 1, 1, 0, 0, 1]

Explanation
TopVotedCandidate topVotedCandidate = new TopVotedCandidate([0, 1, 1, 0, 0, 1, 0], [0, 5, 10, 15, 20, 25, 30]);
topVotedCandidate.q(3); // return 0, At time 3, the votes are [0], and 0 is leading.
topVotedCandidate.q(12); // return 1, At time 12, the votes are [0,1,1], and 1 is leading.
topVotedCandidate.q(25); // return 1, At time 25, the votes are [0,1,1,0,0,1], and 1 is leading (as ties go to the most recent vote.)
topVotedCandidate.q(15); // return 0
topVotedCandidate.q(24); // return 0
topVotedCandidate.q(8); // return 1

 

Constraints:

  • 1 <= persons.length <= 5000
  • times.length == persons.length
  • 0 <= persons[i] < persons.length
  • 0 <= times[i] <= 109
  • times is sorted in a strictly increasing order.
  • times[0] <= t <= 109
  • At most 104 calls will be made to q.

Solutions

Binary search.

  • class TopVotedCandidate {
        private int[] times;
        private int[] wins;
    
        public TopVotedCandidate(int[] persons, int[] times) {
            int n = persons.length;
            int mx = 0, cur = 0;
            this.times = times;
            wins = new int[n];
            int[] counter = new int[n];
            for (int i = 0; i < n; ++i) {
                int p = persons[i];
                if (++counter[p] >= mx) {
                    mx = counter[p];
                    cur = p;
                }
                wins[i] = cur;
            }
        }
    
        public int q(int t) {
            int left = 0, right = wins.length - 1;
            while (left < right) {
                int mid = (left + right + 1) >>> 1;
                if (times[mid] <= t) {
                    left = mid;
                } else {
                    right = mid - 1;
                }
            }
            return wins[left];
        }
    }
    
    /**
     * Your TopVotedCandidate object will be instantiated and called as such:
     * TopVotedCandidate obj = new TopVotedCandidate(persons, times);
     * int param_1 = obj.q(t);
     */
    
  • class TopVotedCandidate {
    public:
        vector<int> times;
        vector<int> wins;
    
        TopVotedCandidate(vector<int>& persons, vector<int>& times) {
            int n = persons.size();
            wins.resize(n);
            int mx = 0, cur = 0;
            this->times = times;
            vector<int> counter(n);
            for (int i = 0; i < n; ++i) {
                int p = persons[i];
                if (++counter[p] >= mx) {
                    mx = counter[p];
                    cur = p;
                }
                wins[i] = cur;
            }
        }
    
        int q(int t) {
            int left = 0, right = wins.size() - 1;
            while (left < right) {
                int mid = left + right + 1 >> 1;
                if (times[mid] <= t)
                    left = mid;
                else
                    right = mid - 1;
            }
            return wins[left];
        }
    };
    
    /**
     * Your TopVotedCandidate object will be instantiated and called as such:
     * TopVotedCandidate* obj = new TopVotedCandidate(persons, times);
     * int param_1 = obj->q(t);
     */
    
  • class TopVotedCandidate:
        def __init__(self, persons: List[int], times: List[int]):
            mx = cur = 0
            counter = Counter()
            self.times = times
            self.wins = []
            for i, p in enumerate(persons):
                counter[p] += 1
                if counter[p] >= mx:
                    mx, cur = counter[p], p
                self.wins.append(cur)
    
        def q(self, t: int) -> int:
            left, right = 0, len(self.wins) - 1
            while left < right:
                mid = (left + right + 1) >> 1
                if self.times[mid] <= t:
                    left = mid
                else:
                    right = mid - 1
            return self.wins[left]
    
    
    # Your TopVotedCandidate object will be instantiated and called as such:
    # obj = TopVotedCandidate(persons, times)
    # param_1 = obj.q(t)
    
    
  • type TopVotedCandidate struct {
    	times []int
    	wins  []int
    }
    
    func Constructor(persons []int, times []int) TopVotedCandidate {
    	mx, cur, n := 0, 0, len(persons)
    	counter := make([]int, n)
    	wins := make([]int, n)
    	for i, p := range persons {
    		counter[p]++
    		if counter[p] >= mx {
    			mx = counter[p]
    			cur = p
    		}
    		wins[i] = cur
    	}
    	return TopVotedCandidate{times, wins}
    }
    
    func (this *TopVotedCandidate) Q(t int) int {
    	left, right := 0, len(this.wins)-1
    	for left < right {
    		mid := (left + right + 1) >> 1
    		if this.times[mid] <= t {
    			left = mid
    		} else {
    			right = mid - 1
    		}
    	}
    	return this.wins[left]
    }
    
    /**
     * Your TopVotedCandidate object will be instantiated and called as such:
     * obj := Constructor(persons, times);
     * param_1 := obj.Q(t);
     */
    
  • class TopVotedCandidate {
        private times: number[];
        private wins: number[];
    
        constructor(persons: number[], times: number[]) {
            const n = persons.length;
            this.times = times;
            this.wins = new Array<number>(n).fill(0);
            const cnt: Array<number> = new Array<number>(n).fill(0);
            let cur = 0;
            for (let i = 0; i < n; ++i) {
                const p = persons[i];
                cnt[p]++;
                if (cnt[cur] <= cnt[p]) {
                    cur = p;
                }
                this.wins[i] = cur;
            }
        }
    
        q(t: number): number {
            const search = (t: number): number => {
                let l = 0,
                    r = this.times.length;
                while (l < r) {
                    const mid = (l + r) >> 1;
                    if (this.times[mid] > t) {
                        r = mid;
                    } else {
                        l = mid + 1;
                    }
                }
                return l;
            };
            const i = search(t) - 1;
            return this.wins[i];
        }
    }
    
    /**
     * Your TopVotedCandidate object will be instantiated and called as such:
     * var obj = new TopVotedCandidate(persons, times)
     * var param_1 = obj.q(t)
     */
    
    

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