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3280. Convert Date to Binary
Description
You are given a string date
representing a Gregorian calendar date in the yyyy-mm-dd
format.
date
can be written in its binary representation obtained by converting year, month, and day to their binary representations without any leading zeroes and writing them down in year-month-day
format.
Return the binary representation of date
.
Example 1:
Input: date = "2080-02-29"
Output: "100000100000-10-11101"
Explanation:
100000100000, 10, and 11101 are the binary representations of 2080, 02, and 29 respectively.
Example 2:
Input: date = "1900-01-01"
Output: "11101101100-1-1"
Explanation:
11101101100, 1, and 1 are the binary representations of 1900, 1, and 1 respectively.
Constraints:
date.length == 10
date[4] == date[7] == '-'
, and all otherdate[i]
's are digits.- The input is generated such that
date
represents a valid Gregorian calendar date between Jan 1st, 1900 and Dec 31st, 2100 (both inclusive).
Solutions
Solution 1: Simulation
We first split the string $\textit{date}$ by -
, then convert each part to its binary representation, and finally join these three parts with -
.
The time complexity is $O(n)$, and the space complexity is $O(n)$. Here, $n$ is the length of the string $\textit{date}$.
-
class Solution { public String convertDateToBinary(String date) { List<String> ans = new ArrayList<>(); for (var s : date.split("-")) { int x = Integer.parseInt(s); ans.add(Integer.toBinaryString(x)); } return String.join("-", ans); } }
-
class Solution { public: string convertDateToBinary(string date) { auto bin = [](string s) -> string { string t = bitset<32>(stoi(s)).to_string(); return t.substr(t.find('1')); }; return bin(date.substr(0, 4)) + "-" + bin(date.substr(5, 2)) + "-" + bin(date.substr(8, 2)); } };
-
class Solution: def convertDateToBinary(self, date: str) -> str: return "-".join(f"{int(s):b}" for s in date.split("-"))
-
func convertDateToBinary(date string) string { ans := []string{} for _, s := range strings.Split(date, "-") { x, _ := strconv.Atoi(s) ans = append(ans, strconv.FormatUint(uint64(x), 2)) } return strings.Join(ans, "-") }
-
function convertDateToBinary(date: string): string { return date .split('-') .map(s => (+s).toString(2)) .join('-'); }