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3280. Convert Date to Binary

Description

You are given a string date representing a Gregorian calendar date in the yyyy-mm-dd format.

date can be written in its binary representation obtained by converting year, month, and day to their binary representations without any leading zeroes and writing them down in year-month-day format.

Return the binary representation of date.

 

Example 1:

Input: date = "2080-02-29"

Output: "100000100000-10-11101"

Explanation:

100000100000, 10, and 11101 are the binary representations of 2080, 02, and 29 respectively.

Example 2:

Input: date = "1900-01-01"

Output: "11101101100-1-1"

Explanation:

11101101100, 1, and 1 are the binary representations of 1900, 1, and 1 respectively.

 

Constraints:

  • date.length == 10
  • date[4] == date[7] == '-', and all other date[i]'s are digits.
  • The input is generated such that date represents a valid Gregorian calendar date between Jan 1st, 1900 and Dec 31st, 2100 (both inclusive).

Solutions

Solution 1: Simulation

We first split the string $\textit{date}$ by -, then convert each part to its binary representation, and finally join these three parts with -.

The time complexity is $O(n)$, and the space complexity is $O(n)$. Here, $n$ is the length of the string $\textit{date}$.

  • class Solution {
        public String convertDateToBinary(String date) {
            List<String> ans = new ArrayList<>();
            for (var s : date.split("-")) {
                int x = Integer.parseInt(s);
                ans.add(Integer.toBinaryString(x));
            }
            return String.join("-", ans);
        }
    }
    
    
  • class Solution {
    public:
        string convertDateToBinary(string date) {
            auto bin = [](string s) -> string {
                string t = bitset<32>(stoi(s)).to_string();
                return t.substr(t.find('1'));
            };
            return bin(date.substr(0, 4)) + "-" + bin(date.substr(5, 2)) + "-" + bin(date.substr(8, 2));
        }
    };
    
    
  • class Solution:
        def convertDateToBinary(self, date: str) -> str:
            return "-".join(f"{int(s):b}" for s in date.split("-"))
    
    
  • func convertDateToBinary(date string) string {
    	ans := []string{}
    	for _, s := range strings.Split(date, "-") {
    		x, _ := strconv.Atoi(s)
    		ans = append(ans, strconv.FormatUint(uint64(x), 2))
    	}
    	return strings.Join(ans, "-")
    }
    
    
  • function convertDateToBinary(date: string): string {
        return date
            .split('-')
            .map(s => (+s).toString(2))
            .join('-');
    }
    
    

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