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3050. Pizza Toppings Cost Analysis
Description
Table: Toppings
+++ \ Column Name \ Type \ +++ \ topping_name \ varchar \ \ cost \ decimal \ +++ topping_name is the primary key for this table. Each row of this table contains topping name and the cost of the topping.
Write a solution to calculate the total cost of all possible 3
topping pizza combinations from a given list of toppings. The total cost of toppings must be rounded to 2
decimal places.
Note:
 Do not include the pizzas where a topping is repeated. For example, ‘Pepperoni, Pepperoni, Onion Pizza’.
 Toppings must be listed in alphabetical order. For example, 'Chicken, Onions, Sausage'. 'Onion, Sausage, Chicken' is not acceptable.
Return the result table ordered by total cost in descending order and combination of toppings in ascending order.
The result format is in the following example.
Example 1:
Input: Toppings table: +++ \ topping_name \ cost \ +++ \ Pepperoni \ 0.50 \ \ Sausage \ 0.70 \ \ Chicken \ 0.55 \ \ Extra Cheese \ 0.40 \ +++ Output: +++ \ pizza \ total_cost \ +++ \ Chicken,Pepperoni,Sausage \ 1.75 \ \ Chicken,Extra Cheese,Sausage \ 1.65 \ \ Extra Cheese,Pepperoni,Sausage \ 1.60 \ \ Chicken,Extra Cheese,Pepperoni \ 1.45 \ +++ Explanation: There are only four different combinations possible with the three topings:  Chicken, Pepperoni, Sausage: Total cost is $1.75 (Chicken $0.55, Pepperoni $0.50, Sausage $0.70).  Chicken, Extra Cheese, Sausage: Total cost is $1.65 (Chicken $0.55, Extra Cheese $0.40, Sausage $0.70).  Extra Cheese, Pepperoni, Sausage: Total cost is $1.60 (Extra Cheese $0.40, Pepperoni $0.50, Sausage $0.70).  Chicken, Extra Cheese, Pepperoni: Total cost is $1.45 (Chicken $0.55, Extra Cheese $0.40, Pepperoni $0.50). Output table is ordered by the total cost in descending order.
Solutions
Solution 1: Window Function + Conditional Join
First, we use a window function to sort the table by the topping_name
field and add a rk
field to each row, representing the ranking of the current row.
Then we use conditional join to join the table T
three times, named as t1
, t2
, t3
respectively. The join conditions are t1.rk < t2.rk
and t2.rk < t3.rk
. After that, we calculate the total price of the three toppings, sort by total price in descending order, and then sort by topping name in ascending order.

# Write your MySQL query statement below WITH T AS ( SELECT *, RANK() OVER (ORDER BY topping_name) AS rk FROM Toppings ) SELECT CONCAT(t1.topping_name, ',', t2.topping_name, ',', t3.topping_name) AS pizza, t1.cost + t2.cost + t3.cost AS total_cost FROM T AS t1 JOIN T AS t2 ON t1.rk < t2.rk JOIN T AS t3 ON t2.rk < t3.rk ORDER BY 2 DESC, 1 ASC;