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2794. Create Object from Two Arrays

Description

Given two arrays keysArr and valuesArr, return a new object obj. Each key-value pair in obj should come from keysArr[i] and valuesArr[i].

If a duplicate key exists at a previous index, that key-value should be excluded. In other words, only the first key should be added to the object.

If the key is not a string, it should be converted into a string by calling String() on it.

 

Example 1:

Input: keysArr = ["a", "b", "c"], valuesArr = [1, 2, 3]
Output: {"a": 1, "b": 2, "c": 3}
Explanation: The keys "a", "b", and "c" are paired with the values 1, 2, and 3 respectively.

Example 2:

Input: keysArr = ["1", 1, false], valuesArr = [4, 5, 6]
Output: {"1": 4, "false": 6}
Explanation: First, all the elements in keysArr are converted into strings. We can see there are two occurrences of "1". The value associated with the first occurrence of "1" is used: 4.

Example 3:

Input: keysArr = [], valuesArr = []
Output: {}
Explanation: There are no keys so an empty object is returned.

 

Constraints:

• keysArr and valuesArr are valid JSON arrays
• 2 <= JSON.stringify(keysArr).length, JSON.stringify(valuesArr).length <= 5 * 105
• keysArr.length === valuesArr.length

Solutions

• TypeScript
• Javascript

• function createObject(keysArr: any[], valuesArr: any[]): Record<string, any> {
      const ans: Record<string, any> = {};
      for (let i = 0; i < keysArr.length; ++i) {
          const k = String(keysArr[i]);
          if (ans[k] === undefined) {
              ans[k] = valuesArr[i];
          }
      }
      return ans;
  }
  
  

• /**
   * @param {Array} keysArr
   * @param {Array} valuesArr
   * @return {Object}
   */
  var createObject = function (keysArr, valuesArr) {
      const ans = {};
      for (let i = 0; i < keysArr.length; ++i) {
          const k = keysArr[i] + '';
          if (ans[k] === undefined) {
              ans[k] = valuesArr[i];
          }
      }
      return ans;
  };
  
  

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