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2781. Length of the Longest Valid Substring

Description

You are given a string word and an array of strings forbidden.

A string is called valid if none of its substrings are present in forbidden.

Return the length of the longest valid substring of the string word.

A substring is a contiguous sequence of characters in a string, possibly empty.

 

Example 1:

Input: word = "cbaaaabc", forbidden = ["aaa","cb"]
Output: 4
Explanation: There are 11 valid substrings in word: "c", "b", "a", "ba", "aa", "bc", "baa", "aab", "ab", "abc" and "aabc". The length of the longest valid substring is 4. 
It can be shown that all other substrings contain either "aaa" or "cb" as a substring. 

Example 2:

Input: word = "leetcode", forbidden = ["de","le","e"]
Output: 4
Explanation: There are 11 valid substrings in word: "l", "t", "c", "o", "d", "tc", "co", "od", "tco", "cod", and "tcod". The length of the longest valid substring is 4.
It can be shown that all other substrings contain either "de", "le", or "e" as a substring. 

 

Constraints:

• 1 <= word.length <= 105
• word consists only of lowercase English letters.
• 1 <= forbidden.length <= 105
• 1 <= forbidden[i].length <= 10
• forbidden[i] consists only of lowercase English letters.

Solutions

• Java
• C++
• Python
• Go
• TypeScript

• class Solution {
      public int longestValidSubstring(String word, List<String> forbidden) {
          var s = new HashSet<>(forbidden);
          int ans = 0, n = word.length();
          for (int i = 0, j = 0; j < n; ++j) {
              for (int k = j; k > Math.max(j - 10, i - 1); --k) {
                  if (s.contains(word.substring(k, j + 1))) {
                      i = k + 1;
                      break;
                  }
              }
              ans = Math.max(ans, j - i + 1);
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      int longestValidSubstring(string word, vector<string>& forbidden) {
          unordered_set<string> s(forbidden.begin(), forbidden.end());
          int ans = 0, n = word.size();
          for (int i = 0, j = 0; j < n; ++j) {
              for (int k = j; k > max(j - 10, i - 1); --k) {
                  if (s.count(word.substr(k, j - k + 1))) {
                      i = k + 1;
                      break;
                  }
              }
              ans = max(ans, j - i + 1);
          }
          return ans;
      }
  };
  

• class Solution:
      def longestValidSubstring(self, word: str, forbidden: List[str]) -> int:
          s = set(forbidden)
          ans = i = 0
          for j in range(len(word)):
              for k in range(j, max(j - 10, i - 1), -1):
                  if word[k : j + 1] in s:
                      i = k + 1
                      break
              ans = max(ans, j - i + 1)
          return ans
  
  

• func longestValidSubstring(word string, forbidden []string) (ans int) {
  	s := map[string]bool{}
  	for _, x := range forbidden {
  		s[x] = true
  	}
  	n := len(word)
  	for i, j := 0, 0; j < n; j++ {
  		for k := j; k > max(j-10, i-1); k-- {
  			if s[word[k:j+1]] {
  				i = k + 1
  				break
  			}
  		}
  		ans = max(ans, j-i+1)
  	}
  	return
  }
  
  func max(a, b int) int {
  	if a > b {
  		return a
  	}
  	return b
  }
  

• function longestValidSubstring(word: string, forbidden: string[]): number {
      const s: Set<string> = new Set(forbidden);
      const n = word.length;
      let ans = 0;
      for (let i = 0, j = 0; j < n; ++j) {
          for (let k = j; k > Math.max(j - 10, i - 1); --k) {
              if (s.has(word.substring(k, j + 1))) {
                  i = k + 1;
                  break;
              }
          }
          ans = Math.max(ans, j - i + 1);
      }
      return ans;
  }
  
  

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