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Formatted question description: https://leetcode.ca/all/2557.html

2557. Maximum Number of Integers to Choose From a Range II

Description

You are given an integer array banned and two integers n and maxSum. You are choosing some number of integers following the below rules:

• The chosen integers have to be in the range [1, n].
• Each integer can be chosen at most once.
• The chosen integers should not be in the array banned.
• The sum of the chosen integers should not exceed maxSum.

Return the maximum number of integers you can choose following the mentioned rules.

 

Example 1:

Input: banned = [1,4,6], n = 6, maxSum = 4
Output: 1
Explanation: You can choose the integer 3.
3 is in the range [1, 6], and do not appear in banned. The sum of the chosen integers is 3, which does not exceed maxSum.

Example 2:

Input: banned = [4,3,5,6], n = 7, maxSum = 18
Output: 3
Explanation: You can choose the integers 1, 2, and 7.
All these integers are in the range [1, 7], all do not appear in banned, and their sum is 18, which does not exceed maxSum.

 

Constraints:

• 1 <= banned.length <= 105
• 1 <= banned[i] <= n <= 109
• 1 <= maxSum <= 1015

Solutions

Solution 1: Deduplication + Sorting + Binary Search

We can add $0$ and $n + 1$ to the array banned, then deduplicate and sort the array banned.

Next, we enumerate every two adjacent elements $i$ and $j$ in the array banned. The range of selectable integers is $[i + 1, j - 1]$. We use binary search to enumerate the number of elements we can select in this range, find the maximum number of selectable elements, and then add it to $ans$. At the same time, we subtract the sum of these elements from maxSum. If maxSum is less than $0$, we break the loop. Return the answer.

The time complexity is $O(n \times \log n)$, and the space complexity is $O(n)$. Where $n$ is the length of the array banned.

• Java
• C++
• Python
• Go

• class Solution {
      public int maxCount(int[] banned, int n, long maxSum) {
          Set<Integer> black = new HashSet<>();
          black.add(0);
          black.add(n + 1);
          for (int x : banned) {
              black.add(x);
          }
          List<Integer> ban = new ArrayList<>(black);
          Collections.sort(ban);
          int ans = 0;
          for (int k = 1; k < ban.size(); ++k) {
              int i = ban.get(k - 1), j = ban.get(k);
              int left = 0, right = j - i - 1;
              while (left < right) {
                  int mid = (left + right + 1) >>> 1;
                  if ((i + 1 + i + mid) * 1L * mid / 2 <= maxSum) {
                      left = mid;
                  } else {
                      right = mid - 1;
                  }
              }
              ans += left;
              maxSum -= (i + 1 + i + left) * 1L * left / 2;
              if (maxSum <= 0) {
                  break;
              }
          }
          return ans;
      }
  }
  

• class Solution {
  public:
      int maxCount(vector<int>& banned, int n, long long maxSum) {
          banned.push_back(0);
          banned.push_back(n + 1);
          sort(banned.begin(), banned.end());
          banned.erase(unique(banned.begin(), banned.end()), banned.end());
          int ans = 0;
          for (int k = 1; k < banned.size(); ++k) {
              int i = banned[k - 1], j = banned[k];
              int left = 0, right = j - i - 1;
              while (left < right) {
                  int mid = left + ((right - left + 1) / 2);
                  if ((i + 1 + i + mid) * 1LL * mid / 2 <= maxSum) {
                      left = mid;
                  } else {
                      right = mid - 1;
                  }
              }
              ans += left;
              maxSum -= (i + 1 + i + left) * 1LL * left / 2;
              if (maxSum <= 0) {
                  break;
              }
          }
          return ans;
      }
  };
  

• class Solution:
      def maxCount(self, banned: List[int], n: int, maxSum: int) -> int:
          banned.extend([0, n + 1])
          ban = sorted(set(banned))
          ans = 0
          for i, j in pairwise(ban):
              left, right = 0, j - i - 1
              while left < right:
                  mid = (left + right + 1) >> 1
                  if (i + 1 + i + mid) * mid // 2 <= maxSum:
                      left = mid
                  else:
                      right = mid - 1
              ans += left
              maxSum -= (i + 1 + i + left) * left // 2
              if maxSum <= 0:
                  break
          return ans
  
  

• func maxCount(banned []int, n int, maxSum int64) (ans int) {
  	banned = append(banned, []int{0, n + 1}...)
  	sort.Ints(banned)
  	ban := []int{}
  	for i, x := range banned {
  		if i > 0 && x == banned[i-1] {
  			continue
  		}
  		ban = append(ban, x)
  	}
  	for k := 1; k < len(ban); k++ {
  		i, j := ban[k-1], ban[k]
  		left, right := 0, j-i-1
  		for left < right {
  			mid := (left + right + 1) >> 1
  			if int64((i+1+i+mid)*mid/2) <= maxSum {
  				left = mid
  			} else {
  				right = mid - 1
  			}
  		}
  		ans += left
  		maxSum -= int64((i + 1 + i + left) * left / 2)
  		if maxSum <= 0 {
  			break
  		}
  	}
  	return
  }
  

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