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Formatted question description: https://leetcode.ca/all/2517.html
2517. Maximum Tastiness of Candy Basket
Description
You are given an array of positive integers price
where price[i]
denotes the price of the ith
candy and a positive integer k
.
The store sells baskets of k
distinct candies. The tastiness of a candy basket is the smallest absolute difference of the prices of any two candies in the basket.
Return the maximum tastiness of a candy basket.
Example 1:
Input: price = [13,5,1,8,21,2], k = 3 Output: 8 Explanation: Choose the candies with the prices [13,5,21]. The tastiness of the candy basket is: min(|13 - 5|, |13 - 21|, |5 - 21|) = min(8, 8, 16) = 8. It can be proven that 8 is the maximum tastiness that can be achieved.
Example 2:
Input: price = [1,3,1], k = 2 Output: 2 Explanation: Choose the candies with the prices [1,3]. The tastiness of the candy basket is: min(|1 - 3|) = min(2) = 2. It can be proven that 2 is the maximum tastiness that can be achieved.
Example 3:
Input: price = [7,7,7,7], k = 2 Output: 0 Explanation: Choosing any two distinct candies from the candies we have will result in a tastiness of 0.
Constraints:
2 <= k <= price.length <= 105
1 <= price[i] <= 109
Solutions
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class Solution { private int[] price; private int k; public int maximumTastiness(int[] price, int k) { Arrays.sort(price); this.price = price; this.k = k; int left = 0, right = 1000000000; while (left < right) { int mid = (left + right + 1) >> 1; if (check(mid)) { left = mid; } else { right = mid - 1; } } return left; } private boolean check(int x) { int s = price[0]; int cnt = 1; for (int i = 1; i < price.length; ++i) { if (price[i] - s >= x) { s = price[i]; ++cnt; } } return cnt >= k; } }
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class Solution { public: int maximumTastiness(vector<int>& price, int k) { sort(price.begin(), price.end()); int left = 0, right = 1e9; auto check = [&](int x) { int s = price[0]; int cnt = 1; for (int i = 1; i < price.size(); ++i) { if (price[i] - s >= x) { s = price[i]; ++cnt; } } return cnt >= k; }; while (left < right) { int mid = (left + right + 1) >> 1; if (check(mid)) { left = mid; } else { right = mid - 1; } } return left; } };
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class Solution: def maximumTastiness(self, price: List[int], k: int) -> int: def check(x): cnt = 1 s = price[0] for p in price[1:]: if p - s >= x: s = p cnt += 1 return cnt >= k price.sort() left, right = 0, 10**9 while left < right: mid = (left + right + 1) >> 1 if check(mid): left = mid else: right = mid - 1 return left
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func maximumTastiness(price []int, k int) int { sort.Ints(price) check := func(x int) bool { s := price[0] cnt := 1 for _, p := range price[1:] { if p-s >= x { s = p cnt++ } } return cnt >= k } left, right := 0, 1000000000 for left < right { mid := (left + right + 1) >> 1 if check(mid) { left = mid } else { right = mid - 1 } } return left }
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function maximumTastiness(price: number[], k: number): number { price.sort((a, b) => a - b); let l = 0; let r = price[price.length - 1] - price[0]; const check = (x: number): boolean => { let [cnt, pre] = [0, -x]; for (const cur of price) { if (cur - pre >= x) { pre = cur; ++cnt; } } return cnt >= k; }; while (l < r) { const mid = (l + r + 1) >> 1; if (check(mid)) { l = mid; } else { r = mid - 1; } } return l; }
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public class Solution { public int MaximumTastiness(int[] price, int k) { Array.Sort(price); int l = 0, r = price[price.Length - 1] - price[0]; while (l < r) { int mid = (l + r + 1) >> 1; if (check(price, mid, k)) { l = mid; } else { r = mid - 1; } } return l; } private bool check(int[] price, int x, int k) { int cnt = 0, pre = -x; foreach (int cur in price) { if (cur - pre >= x) { ++cnt; pre = cur; } } return cnt >= k; } }