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2600. K Items With the Maximum Sum

Description

There is a bag that consists of items, each item has a number 1, 0, or -1 written on it.

You are given four non-negative integers numOnes, numZeros, numNegOnes, and k.

The bag initially contains:

• numOnes items with 1s written on them.
• numZeroes items with 0s written on them.
• numNegOnes items with -1s written on them.

We want to pick exactly k items among the available items. Return the maximum possible sum of numbers written on the items.

 

Example 1:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2
Output: 2
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2.
It can be proven that 2 is the maximum possible sum.

Example 2:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4
Output: 3
Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3.
It can be proven that 3 is the maximum possible sum.

 

Constraints:

• 0 <= numOnes, numZeros, numNegOnes <= 50
• 0 <= k <= numOnes + numZeros + numNegOnes

Solutions

• Java
• C++
• Python
• Go
• TypeScript
• C#
• RenderScript

• class Solution {
      public int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
          if (numOnes >= k) {
              return k;
          }
          if (numZeros >= k - numOnes) {
              return numOnes;
          }
          return numOnes - (k - numOnes - numZeros);
      }
  }
  

• class Solution {
  public:
      int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
          if (numOnes >= k) {
              return k;
          }
          if (numZeros >= k - numOnes) {
              return numOnes;
          }
          return numOnes - (k - numOnes - numZeros);
      }
  };
  

• class Solution:
      def kItemsWithMaximumSum(
          self, numOnes: int, numZeros: int, numNegOnes: int, k: int
      ) -> int:
          if numOnes >= k:
              return k
          if numZeros >= k - numOnes:
              return numOnes
          return numOnes - (k - numOnes - numZeros)
  
  

• func kItemsWithMaximumSum(numOnes int, numZeros int, numNegOnes int, k int) int {
  	if numOnes >= k {
  		return k
  	}
  	if numZeros >= k-numOnes {
  		return numOnes
  	}
  	return numOnes - (k - numOnes - numZeros)
  }
  

• function kItemsWithMaximumSum(
      numOnes: number,
      numZeros: number,
      numNegOnes: number,
      k: number,
  ): number {
      if (numOnes >= k) {
          return k;
      }
      if (numZeros >= k - numOnes) {
          return numOnes;
      }
      return numOnes - (k - numOnes - numZeros);
  }
  
  

• public class Solution {
      public int KItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
          if (numOnes >= k) {
              return k;
          }
          if (numZeros >= k - numOnes) {
              return numOnes;
          }
          return numOnes - (k - numOnes - numZeros);
      }
  }
  
  

• impl Solution {
      pub fn k_items_with_maximum_sum(
          num_ones: i32,
          num_zeros: i32,
          num_neg_ones: i32,
          k: i32
      ) -> i32 {
          if num_ones > k {
              return k;
          }
  
          if num_ones + num_zeros > k {
              return num_ones;
          }
  
          num_ones - (k - num_ones - num_zeros)
      }
  }
  
  

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