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Formatted question description: https://leetcode.ca/all/2413.html
2413. Smallest Even Multiple
- Difficulty: Easy.
- Related Topics: .
- Similar Questions: Greatest Common Divisor of Strings, Three Divisors, Find Greatest Common Divisor of Array.
Problem
Given a positive integer n
, return the smallest positive integer that is a multiple of **both 2
and n
.
**Example 1:
Input: n = 5
Output: 10
Explanation: The smallest multiple of both 5 and 2 is 10.
Example 2:
Input: n = 6
Output: 6
Explanation: The smallest multiple of both 6 and 2 is 6. Note that a number is a multiple of itself.
Constraints:
1 <= n <= 150
Solution (Java, C++, Python)
-
class Solution { public int smallestEvenMultiple(int n) { int k=2*n; for(int i=2*n;i>=n;i--) { if(i%n==0&&i%2==0) k=i; } return k; } } ############ class Solution { public int smallestEvenMultiple(int n) { return n % 2 == 0 ? n : n * 2; } }
-
class Solution: def smallestEvenMultiple(self, n: int) -> int: return n if n % 2 == 0 else n * 2 ############ # 2413. Smallest Even Multiple # https://leetcode.com/problems/smallest-even-multiple/ class Solution: def smallestEvenMultiple(self, n: int) -> int: for x in range(1, n * 2 + 1): if x % 2 == 0 and x % n == 0: return x return -1
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class Solution { public: int smallestEvenMultiple(int n) { return n % 2 == 0 ? n : n * 2; } };
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func smallestEvenMultiple(n int) int { if n%2 == 0 { return n } return n * 2 }
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function smallestEvenMultiple(n: number): number { return n % 2 === 0 ? n : n * 2; }
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impl Solution { pub fn smallest_even_multiple(n: i32) -> i32 { if n % 2 == 0 { return n; } n * 2 } }
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).