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2437. Number of Valid Clock Times

Description

You are given a string of length 5 called time, representing the current time on a digital clock in the format "hh:mm". The earliest possible time is "00:00" and the latest possible time is "23:59".

In the string time, the digits represented by the ? symbol are unknown, and must be replaced with a digit from 0 to 9.

Return an integer answer, the number of valid clock times that can be created by replacing every ? with a digit from 0 to 9.

 

Example 1:

Input: time = "?5:00"
Output: 2
Explanation: We can replace the ? with either a 0 or 1, producing "05:00" or "15:00". Note that we cannot replace it with a 2, since the time "25:00" is invalid. In total, we have two choices.

Example 2:

Input: time = "0?:0?"
Output: 100
Explanation: Each ? can be replaced by any digit from 0 to 9, so we have 100 total choices.

Example 3:

Input: time = "??:??"
Output: 1440
Explanation: There are 24 possible choices for the hours, and 60 possible choices for the minutes. In total, we have 24 * 60 = 1440 choices.

 

Constraints:

  • time is a valid string of length 5 in the format "hh:mm".
  • "00" <= hh <= "23"
  • "00" <= mm <= "59"
  • Some of the digits might be replaced with '?' and need to be replaced with digits from 0 to 9.

Solutions

Solution 1: Enumeration

We can directly enumerate all times from $00:00$ to $23:59$, then judge whether each time is valid, if so, increment the answer.

After the enumeration ends, return the answer.

The time complexity is $O(24 \times 60)$, and the space complexity is $O(1)$.

Solution 2: Optimized Enumeration

We can separately enumerate hours and minutes, count how many hours and minutes meet the condition, and then multiply them together.

The time complexity is $O(24 + 60)$, and the space complexity is $O(1)$.

  • class Solution {
        public int countTime(String time) {
            int ans = 0;
            for (int h = 0; h < 24; ++h) {
                for (int m = 0; m < 60; ++m) {
                    String s = String.format("%02d:%02d", h, m);
                    int ok = 1;
                    for (int i = 0; i < 5; ++i) {
                        if (s.charAt(i) != time.charAt(i) && time.charAt(i) != '?') {
                            ok = 0;
                            break;
                        }
                    }
                    ans += ok;
                }
            }
            return ans;
        }
    }
    
  • class Solution {
    public:
        int countTime(string time) {
            int ans = 0;
            for (int h = 0; h < 24; ++h) {
                for (int m = 0; m < 60; ++m) {
                    char s[20];
                    sprintf(s, "%02d:%02d", h, m);
                    int ok = 1;
                    for (int i = 0; i < 5; ++i) {
                        if (s[i] != time[i] && time[i] != '?') {
                            ok = 0;
                            break;
                        }
                    }
                    ans += ok;
                }
            }
            return ans;
        }
    };
    
  • class Solution:
        def countTime(self, time: str) -> int:
            def check(s: str, t: str) -> bool:
                return all(a == b or b == '?' for a, b in zip(s, t))
    
            return sum(
                check(f'{h:02d}:{m:02d}', time) for h in range(24) for m in range(60)
            )
    
    
  • func countTime(time string) int {
    	ans := 0
    	for h := 0; h < 24; h++ {
    		for m := 0; m < 60; m++ {
    			s := fmt.Sprintf("%02d:%02d", h, m)
    			ok := 1
    			for i := 0; i < 5; i++ {
    				if s[i] != time[i] && time[i] != '?' {
    					ok = 0
    					break
    				}
    			}
    			ans += ok
    		}
    	}
    	return ans
    }
    
  • function countTime(time: string): number {
        let ans = 0;
        for (let h = 0; h < 24; ++h) {
            for (let m = 0; m < 60; ++m) {
                const s = `${h}`.padStart(2, '0') + ':' + `${m}`.padStart(2, '0');
                let ok = 1;
                for (let i = 0; i < 5; ++i) {
                    if (s[i] !== time[i] && time[i] !== '?') {
                        ok = 0;
                        break;
                    }
                }
                ans += ok;
            }
        }
        return ans;
    }
    
    
  • impl Solution {
        pub fn count_time(time: String) -> i32 {
            let mut ans = 0;
    
            for i in 0..24 {
                for j in 0..60 {
                    let mut ok = true;
                    let t = format!("{:02}:{:02}", i, j);
    
                    for (k, ch) in time.chars().enumerate() {
                        if ch != '?' && ch != t.chars().nth(k).unwrap() {
                            ok = false;
                        }
                    }
    
                    if ok {
                        ans += 1;
                    }
                }
            }
    
            ans
        }
    }
    
    
  • class Solution {
        public int countTime(String time) {
            return f(time.substring(0, 2), 24) * f(time.substring(3), 60);
        }
    
        private int f(String s, int m) {
            int cnt = 0;
            for (int i = 0; i < m; ++i) {
                boolean a = s.charAt(0) == '?' || s.charAt(0) - '0' == i / 10;
                boolean b = s.charAt(1) == '?' || s.charAt(1) - '0' == i % 10;
                cnt += a && b ? 1 : 0;
            }
            return cnt;
        }
    }
    
  • class Solution {
    public:
        int countTime(string time) {
            auto f = [](string s, int m) {
                int cnt = 0;
                for (int i = 0; i < m; ++i) {
                    bool a = s[0] == '?' || s[0] - '0' == i / 10;
                    bool b = s[1] == '?' || s[1] - '0' == i % 10;
                    cnt += a && b;
                }
                return cnt;
            };
            return f(time.substr(0, 2), 24) * f(time.substr(3, 2), 60);
        }
    };
    
  • class Solution:
        def countTime(self, time: str) -> int:
            def f(s: str, m: int) -> int:
                cnt = 0
                for i in range(m):
                    a = s[0] == '?' or (int(s[0]) == i // 10)
                    b = s[1] == '?' or (int(s[1]) == i % 10)
                    cnt += a and b
                return cnt
    
            return f(time[:2], 24) * f(time[3:], 60)
    
    
  • func countTime(time string) int {
    	f := func(s string, m int) (cnt int) {
    		for i := 0; i < m; i++ {
    			a := s[0] == '?' || int(s[0]-'0') == i/10
    			b := s[1] == '?' || int(s[1]-'0') == i%10
    			if a && b {
    				cnt++
    			}
    		}
    		return
    	}
    	return f(time[:2], 24) * f(time[3:], 60)
    }
    
  • function countTime(time: string): number {
        const f = (s: string, m: number): number => {
            let cnt = 0;
            for (let i = 0; i < m; ++i) {
                const a = s[0] === '?' || s[0] === Math.floor(i / 10).toString();
                const b = s[1] === '?' || s[1] === (i % 10).toString();
                if (a && b) {
                    ++cnt;
                }
            }
            return cnt;
        };
        return f(time.slice(0, 2), 24) * f(time.slice(3), 60);
    }
    
    
  • impl Solution {
        pub fn count_time(time: String) -> i32 {
            let f = |s: &str, m: usize| -> i32 {
                let mut cnt = 0;
                let first = s.chars().nth(0).unwrap();
                let second = s.chars().nth(1).unwrap();
    
                for i in 0..m {
                    let a = first == '?' || (first.to_digit(10).unwrap() as usize) == i / 10;
    
                    let b = second == '?' || (second.to_digit(10).unwrap() as usize) == i % 10;
    
                    if a && b {
                        cnt += 1;
                    }
                }
    
                cnt
            };
    
            f(&time[..2], 24) * f(&time[3..], 60)
        }
    }
    
    

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