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2413. Smallest Even Multiple
Description
Given a positive integer n, return the smallest positive integer that is a multiple of both 2 and n.
Example 1:
Input: n = 5 Output: 10 Explanation: The smallest multiple of both 5 and 2 is 10.
Example 2:
Input: n = 6 Output: 6 Explanation: The smallest multiple of both 6 and 2 is 6. Note that a number is a multiple of itself.
Constraints:
1 <= n <= 150
Solutions
Solution 1: Mathematics
If $n$ is even, then the least common multiple (LCM) of $2$ and $n$ is $n$ itself. Otherwise, the LCM of $2$ and $n$ is $n \times 2$.
The time complexity is $O(1)$.
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class Solution { public int smallestEvenMultiple(int n) { return n % 2 == 0 ? n : n * 2; } } -
class Solution { public: int smallestEvenMultiple(int n) { return n % 2 == 0 ? n : n * 2; } }; -
class Solution: def smallestEvenMultiple(self, n: int) -> int: return n if n % 2 == 0 else n * 2 -
func smallestEvenMultiple(n int) int { if n%2 == 0 { return n } return n * 2 } -
function smallestEvenMultiple(n: number): number { return n % 2 === 0 ? n : n * 2; } -
impl Solution { pub fn smallest_even_multiple(n: i32) -> i32 { if n % 2 == 0 { return n; } n * 2 } }