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Formatted question description: https://leetcode.ca/all/2278.html

# 2278. Percentage of Letter in String

• Difficulty: Easy.
• Related Topics: String.
• Similar Questions: Sort Characters By Frequency.

## Problem

Given a string s and a character letter, return** the percentage of characters in s that equal letter rounded down to the nearest whole percent.**

Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.


Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.


Constraints:

• 1 <= s.length <= 100

• s consists of lowercase English letters.

• letter is a lowercase English letter.

## Solution (Java, C++, Python)

• class Solution {
public int percentageLetter(String s, char letter) {
int count = 0;
int n = s.length();
for (int i = 0; i < n; i++) {
if (s.charAt(i) == letter) {
++count;
}
}
return (count * 100) / (n);
}
}

• Todo

• class Solution:
def percentageLetter(self, s: str, letter: str) -> int:
return s.count(letter) * 100 // len(s)

############

# 2278. Percentage of Letter in String
# https://leetcode.com/problems/percentage-of-letter-in-string/

class Solution:
def percentageLetter(self, s: str, letter: str) -> int:
n = len(s)
c = s.count(letter)
​
return int(c / n * 100)



Explain:

nope.

Complexity:

• Time complexity : O(n).
• Space complexity : O(n).