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Formatted question description: https://leetcode.ca/all/2278.html

2278. Percentage of Letter in String

  • Difficulty: Easy.
  • Related Topics: String.
  • Similar Questions: Sort Characters By Frequency.

Problem

Given a string s and a character letter, return** the percentage of characters in s that equal letter rounded down to the nearest whole percent.**

  Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

  Constraints:

  • 1 <= s.length <= 100

  • s consists of lowercase English letters.

  • letter is a lowercase English letter.

Solution (Java, C++, Python)

  • class Solution {
    public int percentageLetter(String s, char letter) {
        int count = 0;
        int n = s.length();
        for (int i = 0; i < n; i++) {
            if (s.charAt(i) == letter) {
                ++count;
            }
        }
        return (count * 100) / (n);
    }
}

  • Todo

  • class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        return s.count(letter) * 100 // len(s)

############

# 2278. Percentage of Letter in String
# https://leetcode.com/problems/percentage-of-letter-in-string/

class Solution:
    def percentageLetter(self, s: str, letter: str) -> int:
        n = len(s)
        c = s.count(letter)
​
        return int(c / n * 100)

Explain:

nope.

Complexity:

  • Time complexity : O(n).
  • Space complexity : O(n).

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